NumPy Financial functions: fv() function
numpy.fv() function
The fv() function is used to compute the future value.
Syntax:
numpy.fv(rate, nper, pmt, pv, when='end')[source]
Given:
- a present value, pv
- an interest rate compounded once per period, of which there are
- nper total
- a (fixed) payment, pmt, paid either
- at the beginning (when = {'begin', 1}) or the end (when = {'end', 0}) of each period
Version: 1.15.0
Parameter:
Name | Description | Required / Optional |
---|---|---|
rate | Rate of interest as decimal (not per cent) per period scalar or array_like of shape(M, ) |
Required |
nper | Number of compounding periods scalar or array_like of shape(M, ) |
Required |
pmt | Payment scalar or array_like of shape(M, ) |
Required |
pv | Present value scalar or array_like of shape(M, ) |
Required |
when | When payments are due ('begin' (1) or 'end' (0)). Defaults to {'end', 0}. {{'begin', 1}, {'end', 0}}, {string, int} |
Optional |
Return value: the value at the end of the nper periods
Returns: out : ndarray
Future values. If all input is scalar, returns a scalar float. If any input is array_like, returns future values for each input element.
If multiple inputs are array_like, they all must have the same shape.
Notes:
The future value is computed by solving the equation:
fv + pv*(1+rate)**nper + pmt*(1 + rate*when)/rate*((1 + rate)**nper - 1) == 0
or, when rate == 0:
fv + pv + pmt * nper == 0
NumPy.fv() method Example-1:
What is the future value after 10 years of saving $200 now, with an additional monthly savings of $200. Assume the interest rate is 6% (annually) compounded monthly?
>>> import numpy as np
>>> np.fv(0.06/12, 10*12, -200, -200)
Output:
33139.748708098065
NumPy.fv() method Example-2:
By convention, the negative sign represents cash flow out (i.e. money not available today). Thus, saving $200 a month at 6% annual interest leads to $33,139.75 available to spend in 10 years.
If any input is array_like, returns an array of equal shape. Let's compare different interest rates from the example above.
import numpy as np
x = np.array((0.06, 0.06, 0.07))/12
np.fv(x, 10*12, -200, -200)
Output:
array([33139.7487081 , 33139.7487081 , 35018.89376205])
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