PHP Exercises: Check two given integers and return the value whichever value is nearest to 13 without going over

PHP Basic Algorithm: Exercise-57 with Solution

Write a PHP program to check two given integers and return the value whichever value is nearest to 13 without going over. Return 0 if both numbers go over.

Sample Solution:

PHP Code :

<?php
// Define a function named 'test' that takes two parameters and returns a value based on conditions
function test($x, $y)
{
    // Check if both $x and $y are greater than 13; if true, return 0
    if ($x > 13 && $y > 13) return 0;
    
    // Check if $x is less than or equal to 13 and $y is greater than 13; if true, return $x
    if ($x <= 13 && $y > 13) return $x;
    
    // Check if $y is less than or equal to 13 and $x is greater than 13; if true, return $y
    if ($y <= 13 && $x > 13) return $y;
    
    // If none of the above conditions are met, return the greater of $x and $y
    return $x > $y ? $x : $y;
}

// Test the 'test' function with different input values and display the results
echo (test(4, 5))."\n";
echo (test(7, 12))."\n";
echo (test(10, 13))."\n";
echo (test(17, 33))."\n";
?>

Sample Output:

5
12
13
0

Flowchart:

PHP Code Editor:

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Previous: Write a PHP program to compute the sum of the three given integers. However, if any of the values is in the range 10..20 inclusive then that value counts as 0, except 13 and 17.
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