PHP Exercises: Check two given integers and return the value whichever value is nearest to 13 without going over

PHP Basic Algorithm: Exercise-57 with Solution

Write a PHP program to check two given integers and return the value whichever value is nearest to 13 without going over. Return 0 if both numbers go over.

Sample Solution:

PHP Code :

<?php
// Define a function named 'test' that takes two parameters and returns a value based on conditions
function test($x, $y)
{
    // Check if both $x and $y are greater than 13; if true, return 0
    if ($x > 13 && $y > 13) return 0;
    
    // Check if $x is less than or equal to 13 and $y is greater than 13; if true, return $x
    if ($x <= 13 && $y > 13) return $x;
    
    // Check if $y is less than or equal to 13 and $x is greater than 13; if true, return $y
    if ($y <= 13 && $x > 13) return $y;
    
    // If none of the above conditions are met, return the greater of $x and $y
    return $x > $y ? $x : $y;
}

// Test the 'test' function with different input values and display the results
echo (test(4, 5))."\n";
echo (test(7, 12))."\n";
echo (test(10, 13))."\n";
echo (test(17, 33))."\n";
?>

Explanation:

• Function Purpose:
• The test function takes two parameters, $x and $y, and returns a value based on several conditions involving the numbers' relationship to 13.
• Conditions:
• If both $x and $y are greater than 13, it returns 0.
• If $x is less than or equal to 13 and $y is greater than 13, it returns $x.
• If $y is less than or equal to 13 and $x is greater than 13, it returns $y.
• If none of the above conditions are met, it returns the greater of $x and $y.

Output:

5
12
13
0

Flowchart:

PHP Code Editor:

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