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PHP Exercises: Check a given array of integers, length 3 and create a new array

PHP Basic Algorithm: Exercise-98 with Solution

Write a PHP program to check a given array of integers, length 3 and create a new array. If there is a 5 in the given array immediately followed by a 7 then set 7 to 1.

Sample Solution:

PHP Code :

<?php
function test($numbers)
 { 
    for ($i = 0; $i < sizeof($numbers) - 1; $i++)
            {
                if ($numbers[$i] == 5 && $numbers[$i + 1] == 7)
                    $numbers[$i + 1] = 1;
            }
            return $numbers;
    
 }   

$a = [1, 5, 7];
echo "Original array: " . implode(',', $a) . "\n";
$result = test($a);
echo "New array with maximum values: " . implode(',', $result);

Sample Output:

Original array: 1,5,7
New array with maximum values: 1,5,1

Flowchart:

Flowchart: Check a given array of integers, length 3 and create a new array.

PHP Code Editor:

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Previous: Write a PHP program to check a given array of integers and return true if the array contains 10 or 20 twice. The length of the array will be 0, 1, or 2.
Next: Write a PHP program to compute the sum of the two given arrays of integers, length 3 and find the array which has the largest sum.

What is the difficulty level of this exercise?



PHP: Tips of the Day

$GLOBALS: An associative array containing references to all variables which are currently defined in the global scope of the script. The variable names are the keys of the array

Example:

<?php
$myGlobal = "global"; // declare variable outside of scope
function test()
{
$myLocal = "local"; // declare variable inside of scope
 // both variables are printed
 var_dump($myLocal);
 var_dump($GLOBALS["myGlobal"]);
}
test(); // run function
// only $myGlobal is printed since $myLocal is not globally scoped
 
var_dump($myLocal);
var_dump($myGlobal); 
?>

Output:

string(5) "local"
string(6) "global"
NULL
string(6) "global"

In the above example $myLocal is not displayed the second time because it is declared inside the test() function and then destroyed after the function is closed.

Becoming global

To remedy this there are two options.

Option one: global keyword

function test()
{
 global $myLocal;
 $myLocal = "local";
 var_dump($myLocal);
 var_dump($GLOBALS["myGlobal"]);
}

The global keyword is a prefix on a variable that forces it to be part of the global scope.

Note that you cannot assign a value to a variable in the same statement as the global keyword. Hence, why I had to assign a value underneath. (It is possible if you remove new lines and spaces but I don't think it is neat. global $myLocal; $myLocal = "local").

Option two: $GLOBALS array

function test()
{
 $GLOBALS["myLocal"] = "local";
 $myLocal = $GLOBALS["myLocal"];
 var_dump($myLocal);
 var_dump($GLOBALS["myGlobal"]);
}

In this example I reassigned $myLocal the value of $GLOBAL["myLocal"] since I find it easier writing a variable name rather than the associative array.