PHP Exercises: Compute the amount of the debt in n months

PHP: Exercise-50 with Solution

Write a PHP program to compute the amount of the debt in n months. The borrowing amount is $100,000 and the loan adds 5% interest of the debt and rounds it to the nearest 1,000 above month by month.

Input:
An integer n (0 ≤ n ≤ 100) .

Sample Solution:

PHP Code:

<?php
// Read an integer from standard input representing the number of years
fscanf(STDIN, '%d', $n);

// Initialize the initial debt amount
$debt = 100000;

// Loop through each year to calculate the debt amount after each year
for ($i = 0; $i < $n; $i++) {
    // Calculate the new debt amount after applying a 5% increase and rounding to the nearest thousand
    $debt = ceil(($debt * 1.05) / 1000) * 1000;
}

// Print the final amount of debt
echo "\nAmount of debt: ";
echo $debt . PHP_EOL;

?>

Explanation:

• Reading Input:
• The program reads an integer from standard input (STDIN) that represents the number of years ($n) using fscanf(STDIN, '%d', $n);.
• Initializing Debt:
• A variable $debt is initialized to 100,000, representing the starting amount of debt.
• Loop Through Years:
• A for loop runs from 0 to $n - 1, iterating over each year to calculate the debt for each year.
• Calculating New Debt:
• Inside the loop, the new debt amount is calculated by applying a 5% increase:
• ($debt * 1.05) calculates the increased debt.
• This amount is then divided by 1000, rounded up to the nearest whole number using ceil(), and multiplied back by 1000 to round to the nearest thousand.
• Outputting Final Debt:
• After the loop completes, the final amount of debt is printed to the standard output, preceded by the message "Amount of debt: ".

Output:

Amount of debt: 137000

Flowchart:

PHP Code Editor:

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