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Python: Sum of all items of a given array of integers where each integer is multiplied by its index

Python Basic - 1: Exercise-100 with Solution

Write a Python program to compute the sum of all items in a given array of integers where each integer is multiplied by its index. Return 0 if there is no number.

Sample Solution:

Python Code:

def sum_index_multiplier(nums):
	return sum(j*i for i, j in enumerate(nums))

print(sum_index_multiplier([1,2,3,4]))
print(sum_index_multiplier([-1,-2,-3,-4]))
print(sum_index_multiplier([]))

Sample Output:

20
-20
0

Pictorial Presentation:

Python: Sum of all items of a given array of integers where each integer is multiplied by its index.

Flowchart:

Flowchart: Python - Sum of all items of a given array of integers where each integer is multiplied by its index.

Python Code Editor:

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Python: Tips of the Day

Returns the symmetric difference between two lists, after applying the provided function to each list element of both:

Example:

def tips_symmetric_difference_by(p, q, fn):
  _p, _q = set(map(fn, p)), set(map(fn, q))
  return [item for item in p if fn(item) not in _q] + [item for item in q if fn(item) not in _p]
from math import floor
print(tips_symmetric_difference_by([4.2, 2.4], [4.6, 6.8],floor))

Output:

[2.4, 6.8]

 

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