Python: Find the name of the oldest student from a given dictionary

Python Basic - 1: Exercise-101 with Solution

Write a Python program to find the name of the oldest student from a given dictionary containing the names and ages of a group of students.

Sample Solution:

Python Code:

def oldest_student(students):
	return max(students, key=students.get)

print(oldest_student({"Bernita Ahner": 12, "Kristie Marsico": 11, 
                      "Sara Pardee": 14, "Fallon Fabiano": 11, 
                      "Nidia Dominique": 15})) 
print(oldest_student({"Nilda Woodside": 12, "Jackelyn Pineda": 12.2, 
                      "Sofia Park": 12.4, "Joannie Archibald": 12.6, 
                      "Becki Saunder": 12.7})) 

Sample Output:

Nidia Dominique
Becki Saunder


Flowchart: Python - Find the name of the oldest student from a given dictionary.

Python Code Editor:

Have another way to solve this solution? Contribute your code (and comments) through Disqus.

Previous: Write a Python program to compute the sum of all items of a given array of integers where each integer is multiplied by its index.
Next: Write a Python program to create a new string with no duplicate consecutive letters from a given string.

What is the difficulty level of this exercise?

Test your Programming skills with w3resource's quiz.

Python: Tips of the Day

Iterating over dictionaries using 'for' loops:

I am a bit puzzled by the following code: d = {'x': 1, 'y': 2, 'z': 3} for key in d: print key, 'corresponds to', d[key] What I don't understand is the key portion. How does Python recognize ...

key is just a variable name.

for key in d:

For Python 3.x:

for key, value in d.items():

For Python 2.x:

for key, value in d.iteritems():

To test for yourself, change the word key to poop.

In Python 3.x, iteritems() was replaced with simply items(), which returns a set-like view backed by the dict, like iteritems() but even better. This is also available in 2.7 as viewitems().

The operation items() will work for both 2 and 3, but in 2 it will return a list of the dictionary's (key, value) pairs, which will not reflect changes to the dict that happen after the items() call. If you want the 2.x behavior in 3.x, you can call list(d.items()).

Ref: https://bit.ly/37dm0Qo