﻿ Python: Compute the amount of the debt in n months - w3resource # Python: Compute the amount of the debt in n months

## Python Basic - 1: Exercise-36 with Solution

Write a Python program to compute the amount of the debt in n months. The borrowing amount is \$100,000 and the loan adds 5% interest of the debt and rounds it to the nearest 1,000 above month by month.

Input:
An integer n (0 ≤ n ≤ 100).

Sample Solution:

Python Code:

``````def round_n(n):
if n%1000:
return (1+n//1000)*1000
else:
return n

def compute_debt(n):
if n==0: return 100000
return int(round_n(compute_debt(n-1)*1.05))

print("Input number of months:")
result = compute_debt(int(input()))
print("Amount of debt: ","\$"+str(result).strip())
``````

Sample Output:

```Input number of months:
7
Amount of debt:  \$144000
```

Flowchart: Python Code Editor:

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## Python: Tips of the Day

Returns the symmetric difference between two lists, after applying the provided function to each list element of both

Example:

```def tips_symmetric_difference_by(p, q, fn):
_p, _q = set(map(fn, p)), set(map(fn, q))
return [item for item in p if fn(item) not in _q] + [item for item in q if fn(item) not in _p]
from math import floor
print(tips_symmetric_difference_by([4.2, 2.4], [4.6, 6.8],floor))
```

Output:

```[2.4, 6.8]
```