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Python: Find the highest and lowest number from a given string of space separated integers

Python Basic - 1: Exercise-97 with Solution

Write a Python program to find the highest and lowest number from a given string of space separated integers.

Sample Solution:

Python Code:

def highest_lowest_num(str1):
 num_list = list(map(int, str1.split()))
 return max(num_list), min(num_list)
text = "1 4 5 77 9 0"
print("Original string:", text)
print("Highest and lowest number of the said string:",highest_lowest_num(text))
text = "-1 -4 -5 -77 -9 0"
print("\nOriginal string:", text)
print("Highest and lowest number of the said string:",highest_lowest_num(text))
text = "0 0"
print("\nOriginal string:", text)
print("Highest and lowest number of the said string:",highest_lowest_num(text))

Sample Output:

Original string: 1 4 5 77 9 0
Highest and lowest number of the said string: (77, 0)

Original string: -1 -4 -5 -77 -9 0
Highest and lowest number of the said string: (0, -77)

Original string: 0 0
Highest and lowest number of the said string: (0, 0)

Pictorial Presentation:

Python: Find the highest and lowest number from a given string of space separated integers.
Python: Find the highest and lowest number from a given string of space separated integers.

Flowchart:

Flowchart: Python - Find the highest and lowest number from a given string of space separated integers.

Python Code Editor:

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Previous: Write a Python program to check whether a given number is a narcissistic number or not.
Next: Write a Python program to check whether a sequence of numbers has an increasing trend or not.

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Python: Tips of the Day

How to make a flat list out of list of lists?

Given a list of lists l

flat_list = [item for sublist in l for item in sublist]

which means:

flat_list = []
for sublist in l:
    for item in sublist:
        flat_list.append(item)

is faster than the shortcuts posted so far. (l is the list to flatten.) Here is the corresponding function:

flatten = lambda l: [item for sublist in l for item in sublist]

As evidence, you can use the timeit module in the standard library:

$ python -mtimeit -s'l=[[1,2,3],[4,5,6], [7], [8,9]]*99' '[item for sublist in l for item in sublist]'
10000 loops, best of 3: 143 usec per loop
$ python -mtimeit -s'l=[[1,2,3],[4,5,6], [7], [8,9]]*99' 'sum(l, [])'
1000 loops, best of 3: 969 usec per loop
$ python -mtimeit -s'l=[[1,2,3],[4,5,6], [7], [8,9]]*99' 'reduce(lambda x,y: x+y,l)'
1000 loops, best of 3: 1.1 msec per loop

Explanation: the shortcuts based on + (including the implied use in sum) are, of necessity, O(L**2) when there are L sublists -- as the intermediate result list keeps getting longer, at each step a new intermediate result list object gets allocated, and all the items in the previous intermediate result must be copied over (as well as a few new ones added at the end). So, for simplicity and without actual loss of generality, say you have L sublists of I items each: the first I items are copied back and forth L-1 times, the second I items L-2 times, and so on; total number of copies is I times the sum of x for x from 1 to L excluded, i.e., I * (L**2)/2.

The list comprehension just generates one list, once, and copies each item over (from its original place of residence to the result list) also exactly once.

Ref: https://bit.ly/3dKsNTR