﻿ Python: Count the frequency of the elements of a given unordered list - w3resource

# Python: Count the frequency of the elements of a given unordered list

## Python Itertools: Exercise-32 with Solution

Write a Python program to count the frequency of the elements of a given unordered list.

Sample Solution:

Python Code:

``````from itertools import groupby

uno_list = [2,1,3,8,5,1,4,2,3,4,0,8,2,0,8,4,2,3,4,2]
print("Original list:")
print(uno_list)
uno_list.sort()
print(uno_list)
print("\nSort the said unordered list:")
print(uno_list)
print("\nFrequency of the elements of the said unordered list:")
result = [len(list(group)) for key, group in groupby(uno_list)]
print(result)
```
```

Sample Output:

```Original list:
[2, 1, 3, 8, 5, 1, 4, 2, 3, 4, 0, 8, 2, 0, 8, 4, 2, 3, 4, 2]
[0, 0, 1, 1, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4, 4, 4, 5, 8, 8, 8]

Sort the said unordered list:
[0, 0, 1, 1, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4, 4, 4, 5, 8, 8, 8]

Frequency of the elements of the said unordered list:
[2, 2, 5, 3, 4, 1, 3]
```

Python Code Editor:

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﻿

## Python: Tips of the Day

Inverts a dictionary with non-unique hashable values:

Example:

```def tips_collect_dictionary(obj):
inv_obj = {}
for key, value in obj.items():
inv_obj.setdefault(value, list()).append(key)
return inv_obj
ages = {
"Owen": 25,
"Jhon": 25,
"Pepe": 15,
}
print(tips_collect_dictionary(ages))
```

Output:

```{25: ['Owen', 'Jhon'], 15: ['Pepe']}
```

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