Python: Check whether all dictionaries in a list are empty or not
Python List: Exercise - 71 with Solution
Write a Python program to check whether all dictionaries in a list are empty or not.
Sample Solution:
Python Code:
my_list = [{},{},{}]
my_list1 = [{1:2},{},{}]
print(all(not d for d in my_list))
print(all(not d for d in my_list1))
Sample Output:
True False
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Python: Tips of the Day
Creates a list of elements, grouped based on the position in the original lists:
Example:
def tips_zip(*args, fill_value=None): max_length = max([len(lst) for lst in args]) result = [] for i in range(max_length): result.append([ args[k][i] if i < len(args[k]) else fillvalue for k in range(len(args)) ]) return result print(tips_zip(['a', 'b'], [1, 2], [True, False])) print(tips_zip(['a'], [1, 2], [True, False])) print(tips_zip(['a'], [1, 2], [True, False], fill_value = '1'))
Output:
[['a', 1, True], ['b', 2, False]] [['a', 1, True], [None, 2, False]] [['a', 1, True], ['1', 2, False]]
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