Python Math: Find out, if the given number is abundant

Last update on April 24 2025 12:44:42 (UTC/GMT +8 hours)

13. Abundant Number Checker

Write a Python program to find out if the given number is abundant.
Note: In number theory, an abundant number or excessive number is a number for which the sum of its proper divisors is greater than the number itself. The integer 12 is the first abundant number. Its proper divisors are 1, 2, 3, 4 and 6 for a total of 16.

Sample Solution:

Python Code:

def is_abundant(n):
    fctr_sum = sum([fctr for fctr in range(1, n) if n % fctr == 0])
    return fctr_sum > n
print(is_abundant(12))
print(is_abundant(13))

Sample Output:

True                                                                                                          
False

Pictorial Presentation:

Flowchart:

For more Practice: Solve these Related Problems:

• Write a Python program that determines if a given number is abundant by comparing the sum of its proper divisors to the number itself.
• Write a Python function to list all abundant numbers in a given range and then print them.
• Write a Python script to prompt the user for a number, check if it is abundant, and print an appropriate message.
• Write a Python program to compare two numbers and indicate which one is more abundant (or if neither is abundant), using divisor summation.

Go to:

• Python Math Exercises Home ↩
• Python Exercises Home ↩

Previous: Write a Python program to calculate the sum of all digits of the base to the specified power.
Next: Write a Python program to sum all amicable numbers from 1 to specified numbers.

Python Code Editor:

Have another way to solve this solution? Contribute your code (and comments) through Disqus.