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Python Math: Find out, if the given number is abundant

Python Math: Exercise-13 with Solution

Write a Python program to find out, if the given number is abundant.
Note: In number theory, an abundant number or excessive number is a number for which the sum of its proper divisors is greater than the number itself. The integer 12 is the first abundant number. Its proper divisors are 1, 2, 3, 4 and 6 for a total of 16.

Sample Solution:-

Python Code:

def is_abundant(n):
    fctr_sum = sum([fctr for fctr in range(1, n) if n % fctr == 0])
    return fctr_sum > n
print(is_abundant(12))
print(is_abundant(13))

Sample Output:

True                                                                                                          
False

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Python Math: Find out, if the given number is abundant

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Flowchart: Find out, if the given number is abundant

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Previous: Write a Python program to calculate the sum of all digits of the base to the specified power.
Next: Write a Python program to sum all amicable numbers from 1 to specified numbers.

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Python: Tips of the Day

Lambdas for Sorting:

>>> students = [{'name': 'John', 'score': 98}, {'name': 'Mike', 'score': 94}, {'name': 'Jennifer', 'score': 99}]
>>> sorted(students, key=lambda x: x['score'])
[{'name': 'Mike', 'score': 94}, {'name': 'John', 'score': 98}, {'name': 'Jennifer', 'score': 99}]