﻿ Python Math: Generate a square matrix filled with elements from 1 to n2 in spiral order - w3resource

# Python Math: Generate a square matrix filled with elements from 1 to n raised to the power of 2 in spiral order

## Python Math: Exercise-73 with Solution

Write a Python program to generate (given an integer n) a square matrix filled with elements from 1 to n raised to the power of 2 in spiral order.

Sample Solution:-

Python Code:

``````#https://gist.github.com/Ray1988/6806c1b85af70388a277
def generateMatrix(n):
if n<=0:
return []

matrix=[row[:] for row in [*n]*n]

row_st=0
row_ed=n-1

col_st=0
col_ed=n-1
current=1

while (True):
if current>n*n:
break
for c in range (col_st, col_ed+1):
matrix[row_st][c]=current
current+=1
row_st+=1
for r in range (row_st, row_ed+1):
matrix[r][col_ed]=current
current+=1
col_ed-=1
for c in range (col_ed, col_st-1, -1):
matrix[row_ed][c]=current
current+=1
row_ed-=1
for r in range (row_ed, row_st-1, -1):
matrix[r][col_st]=current
current+=1
col_st+=1
return matrix

print(list(generateMatrix(3)))
```
```

Sample Output:

```[[1, 2, 3], [8, 9, 4], [7, 6, 5]]
```

Pictorial Presentation: Flowchart: ## Visualize Python code execution:

The following tool visualize what the computer is doing step-by-step as it executes the said program:

Python Code Editor:

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## Python: Tips of the Day

Given each iterable to construct a tuple by adding an index:

```>>> a = ['Hello', 'world', '!']
>>> list(enumerate(a))
[(0, 'Hello'), (1, 'world'), (2, '!')]
```

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