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NumPy: Repeat all the elements three times of a given array of string

NumPy String: Exercise-2 with Solution

Write a NumPy program to repeat all the elements three times of a given array of string.

Sample Solution:-

Python Code:

import numpy as np
x1 = np.array(['Python', 'PHP', 'Java', 'C++'], dtype=np.str)
print("Original Array:")
print(x1)
new_array = np.char.multiply(x1, 3)
print("New array:")
print(new_array)

Sample Input:

(['Python', 'PHP', 'Java', 'C++'], dtype=np.str)

Sample Output:

Original Array:
['Python' 'PHP' 'Java' 'C++']
New array:
['PythonPythonPython' 'PHPPHPPHP' 'JavaJavaJava' 'C++C++C++']

Pictorial Presentation:

NumPy String: Repeat all the elements three times of a given array of string

Python Code Editor:

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Python: Tips of the Day

Getting the last element of a list:

some_list[-1] is the shortest and most Pythonic.

In fact, you can do much more with this syntax. The some_list[-n] syntax gets the nth-to-last element. So some_list[-1] gets the last element, some_list[-2] gets the second to last, etc, all the way down to some_list[-len(some_list)], which gives you the first element.

You can also set list elements in this way. For instance:

>>> some_list = [1, 2, 3]
>>> some_list[-1] = 5 # Set the last element
>>> some_list[-2] = 3 # Set the second to last element
>>> some_list
[1, 3, 5]

Note that getting a list item by index will raise an IndexError if the expected item doesn't exist. This means that some_list[-1] will raise an exception if some_list is empty, because an empty list can't have a last element.

Ref: https://bit.ly/3d8TfFP