Pandas: Indexes of missing values in a given DataFrame

Last update on May 02 2025 12:50:48 (UTC/GMT +8 hours)

18. Find Indexes of Missing Values

Write a Pandas program to find the Indexes of missing values in a given DataFrame.

Test Data:

     ord_no  purch_amt  sale_amt    ord_date  customer_id  salesman_id
0   70001.0     150.50     10.50  2012-10-05         3002       5002.0
1       NaN        NaN     20.65  2012-09-10         3001       5003.0
2   70002.0      65.26       NaN         NaN         3001       5001.0
3   70004.0     110.50     11.50  2012-08-17         3003          NaN
4       NaN     948.50     98.50  2012-09-10         3002       5002.0
5   70005.0        NaN       NaN  2012-07-27         3001       5001.0
6       NaN    5760.00     57.00  2012-09-10         3001       5001.0
7   70010.0    1983.43     19.43  2012-10-10         3004          NaN
8   70003.0        NaN       NaN  2012-10-10         3003       5003.0
9   70012.0     250.45     25.45  2012-06-27         3002       5002.0
10      NaN      75.29     75.29  2012-08-17         3001       5003.0
11  70013.0    3045.60     35.60  2012-04-25         3001          NaN

Sample Solution:

Python Code :

import pandas as pd
import numpy as np
pd.set_option('display.max_rows', None)
#pd.set_option('display.max_columns', None)
df = pd.DataFrame({
'ord_no':[70001,np.nan,70002,70004,np.nan,70005,np.nan,70010,70003,70012,np.nan,70013],
'purch_amt':[150.5,np.nan,65.26,110.5,948.5,np.nan,5760,1983.43,np.nan,250.45, 75.29,3045.6],
'sale_amt':[10.5,20.65,np.nan,11.5,98.5,np.nan,57,19.43,np.nan,25.45, 75.29,35.6],
'ord_date': ['2012-10-05','2012-09-10',np.nan,'2012-08-17','2012-09-10','2012-07-27','2012-09-10','2012-10-10','2012-10-10','2012-06-27','2012-08-17','2012-04-25'],
'customer_id':[3002,3001,3001,3003,3002,3001,3001,3004,3003,3002,3001,3001],
'salesman_id':[5002,5003,5001,np.nan,5002,5001,5001,np.nan,5003,5002,5003,np.nan]})
print("Original Orders DataFrame:")
print(df) 
print("\nMissing values in purch_amt column:")
result = df['ord_no'].isnull().to_numpy().nonzero()
print(result)

Sample Output:

Original Orders DataFrame:
     ord_no  purch_amt  sale_amt    ord_date  customer_id  salesman_id
0   70001.0     150.50     10.50  2012-10-05         3002       5002.0
1       NaN        NaN     20.65  2012-09-10         3001       5003.0
2   70002.0      65.26       NaN         NaN         3001       5001.0
3   70004.0     110.50     11.50  2012-08-17         3003          NaN
4       NaN     948.50     98.50  2012-09-10         3002       5002.0
5   70005.0        NaN       NaN  2012-07-27         3001       5001.0
6       NaN    5760.00     57.00  2012-09-10         3001       5001.0
7   70010.0    1983.43     19.43  2012-10-10         3004          NaN
8   70003.0        NaN       NaN  2012-10-10         3003       5003.0
9   70012.0     250.45     25.45  2012-06-27         3002       5002.0
10      NaN      75.29     75.29  2012-08-17         3001       5003.0
11  70013.0    3045.60     35.60  2012-04-25         3001          NaN

Missing values in purch_amt column:
(array([ 1,  4,  6, 10]),)

For more Practice: Solve these Related Problems:

Write a Pandas program to determine the row indices where NaN values occur in a DataFrame.
Write a Pandas program to iterate through a DataFrame and return the index positions for all missing entries.
Write a Pandas program to use numpy.where() in combination with isnull() to locate missing values' indexes.
Write a Pandas program to create a list of index positions for missing values in a specified column of a DataFrame.

Go to:

Previous: Write a Pandas program to count the missing values in a given DataFrame.
Next: Write a Pandas program to replace the missing values with the most frequent values present in each column of a given dataframe.

Python Code Editor:

Have another way to solve this solution? Contribute your code (and comments) through Disqus.