AdventureWorks Database: Get the differences between the maximum and minimum orderdate
SQL Query - AdventureWorks: Exercise-115 with Solution
115. From the following table write a query in SQL to find the differences between the maximum and minimum orderdate.
Sample table: Sales.SalesOrderHeadersalesorderid|revisionnumber|orderdate |duedate |shipdate |status|onlineorderflag|purchaseordernumber|accountnumber |customerid|salespersonid|territoryid|billtoaddressid|shiptoaddressid|shipmethodid|creditcardid|creditcardapprovalcode|currencyrateid|subtotal |taxamt |freight |totaldue |comment|rowguid |modifieddate | ------------+--------------+-----------------------+-----------------------+-----------------------+------+---------------+-------------------+--------------+----------+-------------+-----------+---------------+---------------+------------+------------+----------------------+--------------+-----------+----------+---------+-----------+-------+------------------------------------+-----------------------+ 43659| 8|2011-05-31 00:00:00.000|2011-06-12 00:00:00.000|2011-06-07 00:00:00.000| 5|false |PO522145787 |10-4020-000676| 29825| 279| 5| 985| 985| 5| 16281|105041Vi84182 | | 20565.6206| 1971.5149| 616.0984| 23153.2339| |79b65321-39ca-4115-9cba-8fe0903e12e6|2011-06-07 00:00:00.000| 43660| 8|2011-05-31 00:00:00.000|2011-06-12 00:00:00.000|2011-06-07 00:00:00.000| 5|false |PO18850127500 |10-4020-000117| 29672| 279| 5| 921| 921| 5| 5618|115213Vi29411 | | 1294.2529| 124.2483| 38.8276| 1457.3288| |738dc42d-d03b-48a1-9822-f95a67ea7389|2011-06-07 00:00:00.000| 43661| 8|2011-05-31 00:00:00.000|2011-06-12 00:00:00.000|2011-06-07 00:00:00.000| 5|false |PO18473189620 |10-4020-000442| 29734| 282| 6| 517| 517| 5| 1346|85274Vi6854 | 4| 32726.4786| 3153.7696| 985.553| 36865.8012| |d91b9131-18a4-4a11-bc3a-90b6f53e9d74|2011-06-07 00:00:00.000| 43662| 8|2011-05-31 00:00:00.000|2011-06-12 00:00:00.000|2011-06-07 00:00:00.000| 5|false |PO18444174044 |10-4020-000227| 29994| 282| 6| 482| 482| 5| 10456|125295Vi53935 | 4| 28832.5289| 2775.1646| 867.2389| 32474.9324| |4a1ecfc0-cc3a-4740-b028-1c50bb48711c|2011-06-07 00:00:00.000| 43663| 8|2011-05-31 00:00:00.000|2011-06-12 00:00:00.000|2011-06-07 00:00:00.000| 5|false |PO18009186470 |10-4020-000510| 29565| 276| 4| 1073| 1073| 5| 4322|45303Vi22691 | | 419.4589| 40.2681| 12.5838| 472.3108| |9b1e7a40-6ae0-4ad3-811c-a64951857c4b|2011-06-07 00:00:00.000| 43664| 8|2011-05-31 00:00:00.000|2011-06-12 00:00:00.000|2011-06-07 00:00:00.000| 5|false |PO16617121983 |10-4020-000397| 29898| 280| 1| 876| 876| 5| 806|95555Vi4081 | | 24432.6088| 2344.9921| 732.81| 27510.4109| |22a8a5da-8c22-42ad-9241-839489b6ef0d|2011-06-07 00:00:00.000| 43665| 8|2011-05-31 00:00:00.000|2011-06-12 00:00:00.000|2011-06-07 00:00:00.000| 5|false |PO16588191572 |10-4020-000146| 29580| 283| 1| 849| 849| 5| 15232|35568Vi78804 | | 14352.7713| 1375.9427| 429.9821| 16158.6961| |5602c304-853c-43d7-9e79-76e320d476cf|2011-06-07 00:00:00.000| -- more --
Sample Solution:
-- Selecting the time difference between the maximum and minimum OrderDate values from the SalesOrderHeader table
SELECT
-- Calculating the time difference between the maximum and minimum OrderDate values
max(OrderDate) - min(OrderDate)
-- Selecting data from the SalesOrderHeader table
FROM
Sales.SalesOrderHeader;
Explanation:
- This SQL code operates on a table named Sales.SalesOrderHeader.
- It calculates the time difference between the maximum and minimum OrderDate values.
- The max(OrderDate) function returns the maximum (latest) OrderDate value from the SalesOrderHeader table.
- The min(OrderDate) function returns the minimum (earliest) OrderDate value from the SalesOrderHeader table.
- By subtracting the minimum OrderDate from the maximum OrderDate, you get the time duration between the earliest and latest orders.
- The result will be the time difference expressed in the appropriate units based on the data type of the OrderDate column (e.g., days, hours, minutes).
Sample Output:
?column? | ---------+ 1126 days|
SQL AdventureWorks Editor:
Practice Online
Contribute your code and comments through Disqus.
Previous: Get a newdate by adding two days with current date.
Next: Rank the products by the specified inventory locations.
What is the difficulty level of this exercise?
Test your Programming skills with w3resource's quiz.
It will be nice if you may share this link in any developer community or anywhere else, from where other developers may find this content. Thanks.
https://www.w3resource.com/sql-exercises/adventureworks/sql-adventureworks-exercise-115.php
- Weekly Trends and Language Statistics
- Weekly Trends and Language Statistics