SQL Exercises: View to show for each order the salesman and customer

Last update on January 12 2026 12:48:17 (UTC/GMT +8 hours)

6. From the following tables, create a view to get the salesperson and customer by name. Return order name, purchase amount, salesperson ID, name, customer name.

Sample table: Salesman

 salesman_id |    name    |   city   | commission 
-------------+------------+----------+------------
        5001 | James Hoog | New York |       0.15
        5002 | Nail Knite | Paris    |       0.13
        5005 | Pit Alex   | London   |       0.11
        5006 | Mc Lyon    | Paris    |       0.14
        5007 | Paul Adam  | Rome     |       0.13
        5003 | Lauson Hen | San Jose |       0.12

Sample table: Customer

 customer_id |   cust_name    |    city    | grade | salesman_id 
-------------+----------------+------------+-------+-------------
        3002 | Nick Rimando   | New York   |   100 |        5001
        3007 | Brad Davis     | New York   |   200 |        5001
        3005 | Graham Zusi    | California |   200 |        5002
        3008 | Julian Green   | London     |   300 |        5002
        3004 | Fabian Johnson | Paris      |   300 |        5006
        3009 | Geoff Cameron  | Berlin     |   100 |        5003
        3003 | Jozy Altidor   | Moscow     |   200 |        5007
        3001 | Brad Guzan     | London     |       |        5005

Sample table: orders

ord_no      purch_amt   ord_date    customer_id  salesman_id
----------  ----------  ----------  -----------  -----------
70001       150.5       2012-10-05  3005         5002
70009       270.65      2012-09-10  3001         5005
70002       65.26       2012-10-05  3002         5001
70004       110.5       2012-08-17  3009         5003
70007       948.5       2012-09-10  3005         5002
70005       2400.6      2012-07-27  3007         5001
70008       5760        2012-09-10  3002         5001
70010       1983.43     2012-10-10  3004         5006
70003       2480.4      2012-10-10  3009         5003
70012       250.45      2012-06-27  3008         5002
70011       75.29       2012-08-17  3003         5007
70013       3045.6      2012-04-25  3002         5001

Sample Solution:

-- Creating a VIEW named 'nameorders'
CREATE VIEW nameorders

-- Selecting columns 'ord_no', 'purch_amt', 'salesman_id', 'name', and 'cust_name' from the 'orders', 'customer', and 'salesman' tables
-- Using aliases 'a', 'b', and 'c' for the respective tables
-- Joining tables based on matching 'customer_id' and 'salesman_id'
AS SELECT ord_no, purch_amt, a.salesman_id, name, cust_name
FROM orders a, customer b, salesman c
WHERE a.customer_id = b.customer_id
AND a.salesman_id = c.salesman_id;

output:

sqlpractice=# SELECT *
sqlpractice-# FROM nameorders
sqlpractice-# WHERE name = 'Mc Lyon';
 ord_no | purch_amt | salesman_id |  name   |   cust_name
--------+-----------+-------------+---------+----------------
  70010 |   1983.43 |        5006 | Mc Lyon | Fabian Johnson
  70015 |    322.00 |        5006 | Mc Lyon | Varun
(2 rows)

Code Explanation:

The given SQL statement creates a view called "nameorders" that shows the column order number, purchase amount, the salesman ID, the salesman name, and the customer name for each order.
The WHERE clause filters the results to only include rows where the "customer_id" in the 'orders' table matches the "customer_id" in the 'customer' table and the "salesman_id" in the 'orders' table matches the "salesman_id" in the 'salesman' table.

Go to:

PREV : View to keep track the number of customers ordering.
NEXT : View to find salesman with the highest order of a day.

Inventory database model:

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