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PHP JSON - Exercises, Practice, Solution

PHP JSON [ 4 exercises with solution]

1. Write a PHP script to decode a JSON string. Go to the editor
Click me to see the solution

2. Write a PHP script to decode large integers. Go to the editor
Sample integer :
{"number": 123456789012345678901234567890}
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3. Write a PHP script to get JSON representation of a value from an array. Go to the editor
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4. Write a PHP function to display JSON decode errors. Go to the editor
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PHP Code Editor:

More to Come !

Do not submit any solution of the above exercises at here, if you want to contribute go to the appropriate exercise page.



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PHP: How to get a variable name as a string in PHP?

You could use get_defined_vars() to find the name of a variable that has the same value as the one you're trying to find the name of. Obviously this will not always work, since different variables often have the same values, but it's the only way I can think of to do this.

Edit: get_defined_vars() doesn't seem to be working correctly, it returns 'var' because $var is used in the function itself. $GLOBALS seems to work so I've changed it to that.

function print_var_name($var) {
    foreach($GLOBALS as $var_name => $value) {
        if ($value === $var) {
            return $var_name;
        }
    }

    return false;
}

Edit: to be clear, there is no good way to do this in PHP, which is probably because you shouldn't have to do it. There are probably better ways of doing what you're trying to do.

Ref : https://bit.ly/37qFimU