Python Exercises: Check whether a given number is a Disarium number or unhappy number

Python Math: Exercise-88 with Solution

Write a Python program to check whether a given number is a Disarium number or an unhappy number.

A Disarium number is a number defined by the following process:
Sum of its digits powered with their respective position is equal to the original number.
For example 175 is a Disarium number:
As 1¹+3²+5³ = 135
Some other DISARIUM are 89, 175, 518 etc.

Pictorial Presentation:

Sample Solution-1:

Python Code:

def is_disarium(num):
    temp = 0
    for i in range(len(str(num))):
        temp += int(str(num)[i]) ** (i + 1)
    return temp == num

num = 25
print("\nIs",num,"is Disarium number?",is_disarium(num))
num = 89
print("\nIs",num,"is Disarium number?",is_disarium(num))
num = 75
print("\nIs",num,"is Disarium number?",is_disarium(num))
num = 125
print("\nIs",num,"is Disarium number?",is_disarium(num)) 
num = 518
print("\nIs",num,"is Disarium number?",is_disarium(num))

Sample Output:

Is 25 is Disarium number? False

Is 89 is Disarium number? True

Is 75 is Disarium number? False

Is 125 is Disarium number? False

Is 518 is Disarium number? True

Flowchart:

Sample Solution-2:

Python Code:

def is_disarium(num):
    flag = (num == sum([int(str(num)[i-1])**i for i in range(1,len(str(num))+1)]))
    return flag

num = 25
print("\nIs",num,"is Disarium number?",is_disarium(num))
num = 89
print("\nIs",num,"is Disarium number?",is_disarium(num))
num = 75
print("\nIs",num,"is Disarium number?",is_disarium(num))
num = 125
print("\nIs",num,"is Disarium number?",is_disarium(num)) 
num = 518
print("\nIs",num,"is Disarium number?",is_disarium(num))

Sample Output:

Is 25 is Disarium number? False

Is 89 is Disarium number? True

Is 75 is Disarium number? False

Is 125 is Disarium number? False

Is 518 is Disarium number? True

Flowchart:

Python Code Editor:

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