# Python Math: Clamps number within the inclusive range

## Python Math: Exercise-87 with Solution

Write a Python program to cap a number within the inclusive range specified by the given boundary values x and y.

- If num falls within the range (a, b), return num.
- Otherwise, return the nearest number in the range.

**Sample Solution:**

**Python Code:**

```
def clamp_number(num, a, b):
return max(min(num, max(a, b)), min(a, b))
print(clamp_number(2, 4, 7))
print(clamp_number(1, -1, -4))
print(clamp_number(22, -10, 10))
print(clamp_number(20, 1, 10))
print(clamp_number(5, 1, 20))
print(clamp_number(1, 10, 20))
```

Sample Output:

4 -1 10 10 5 10

**Flowchart:**

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## Python: Tips of the Day

**Creating a sequence of numbers (zero to ten with skips):**

>>> range(0,10,2) [0, 2, 4, 6, 8]

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