Python Math: Clamps number within the inclusive range
Python Math: Exercise-87 with Solution
Write a Python program to cap a number within the inclusive range specified by the given boundary values x and y.
- If num falls within the range (a, b), return num.
- Otherwise, return the nearest number in the range.
def clamp_number(num, a, b): return max(min(num, max(a, b)), min(a, b)) print(clamp_number(2, 4, 7)) print(clamp_number(1, -1, -4)) print(clamp_number(22, -10, 10)) print(clamp_number(20, 1, 10)) print(clamp_number(5, 1, 20)) print(clamp_number(1, 10, 20))
4 -1 10 10 5 10
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Python: Tips of the Day
Creating a sequence of numbers (zero to ten with skips):
>>> range(0,10,2) [0, 2, 4, 6, 8]
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