C putc() function
C library function - putc()
The putc() function is used to convert character to unsigned character and then writes character to the output stream at the current position.
Syntax:
int putc(int char, FILE *stream)
Parameters:
Name | Description | Required /Optional |
---|---|---|
char | Character write to the output stream. | Required |
stream | Identifies an address for a file descriptor, which is an area of memory associated with an input or output stream. | Required |
Return value
- Upon successful completion, putc() shall return the value it has written.
- Otherwise, it shall return EOF, the error indicator for the stream shall be set, and errno shall be set to indicate the error.
Example: putc() function
In this example, the contents of a buffer are written to a data stream
#include <stdio.h>
#include <string.h>
#define LEN_STR 80
int main(void)
{
FILE *stream = stdout;
int i, C;
char buffer[LEN_STR + 1] = "C Programming.";
for ( i = 0;
(i < strlen(buffer)) && ((C = putc(buffer[i], stream)) != EOF);
++i);
}
Output:
C Programming.
C Programming Code Editor:
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C Programming: Tips of the Day
Reading a string with scanf :
An array "decays" into a pointer to its first element, so scanf("%s", string) is equivalent to scanf("%s", &string[0]). On the other hand, scanf("%s", &string) passes a pointer-to-char[256], but it points to the same place.
Then scanf, when processing the tail of its argument list, will try to pull out a char *. That's the Right Thing when you've passed in string or &string[0], but when you've passed in &string you're depending on something that the language standard doesn't guarantee, namely that the pointers &string and &string[0] -- pointers to objects of different types and sizes that start at the same place -- are represented the same way.
Ref : https://bit.ly/3pdEk6f
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