C setbuf() function
C library function - setbuf()
The setbuf() function controls buffering for the specified stream if the operating system supports user-defined buffers. The stream pointer must refer to an open file before any I/O or repositioning has been done.
Syntax:
void setbuf(FILE *stream, char *buffer)
setbuf() Parameters:
Name | Description | Required /Optional |
---|---|---|
stream | Identifies an address for a file descriptor, which is an area of memory associated with an input or output stream. | Required |
buffer | The system uses the buffer, which you specify, for input/output buffering instead of the default system-allocated buffer for the given stream. | Required |
Return value from setbuf()
- This function does not return any value.
Example: setbuf() function
The following example opens the file test.txt for writing. As a result, it calls the setbuf() function in order to create a buffer of length BUFSIZ. Strings are written to the stream using the buffer buf, which contains the string before it is flushed to the file.
#include <stdio.h>
#include <string.h>
int main(void)
{
char buf[BUFSIZ];
char string[] = "C Programming.";
FILE *stream;
memset(buf,'\0',BUFSIZ); /* initialize buf to null characters */
stream = fopen("test.txt", "wb");
setbuf(stream,buf); /* set up buffer */
fwrite(string, sizeof(string), 1, stream);
printf("String is found in buffer now. %s\n",buf); /* string is found in buf now */
fclose(stream); /* buffer is flushed out to myfile.dat */
}
Output:
String is found in buffer now. C Programming.
C Programming Code Editor:
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C Programming: Tips of the Day
Reading a string with scanf :
An array "decays" into a pointer to its first element, so scanf("%s", string) is equivalent to scanf("%s", &string[0]). On the other hand, scanf("%s", &string) passes a pointer-to-char[256], but it points to the same place.
Then scanf, when processing the tail of its argument list, will try to pull out a char *. That's the Right Thing when you've passed in string or &string[0], but when you've passed in &string you're depending on something that the language standard doesn't guarantee, namely that the pointers &string and &string[0] -- pointers to objects of different types and sizes that start at the same place -- are represented the same way.
Ref : https://bit.ly/3pdEk6f
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