C puts() function
C library function - puts()
The puts() function is used to write specified string (plus a newline), to the standard output stream. The ending null character is not written.
Syntax:
int puts(const char *str)
Parameters:
Name | Description | Required /Optional |
---|---|---|
str | This is the string to be written. | Required |
Return value
- Upon successful completion, puts() shall return a non-negative number.
- Otherwise, it shall return EOF, shall set an error indicator for the stream, and errno shall be set to indicate the error.
Example: puts() function
#include <stdio.h>
int main()
{
const char *text = "C Programming.";
puts(text);
return 0;
}
Output:
C Programming.
Difference from printf()
- The puts() function prints a newline after the text supplied.
- The puts() function prints the string as it is (% codes are not processed).
C Programming Code Editor:
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C Programming: Tips of the Day
Reading a string with scanf :
An array "decays" into a pointer to its first element, so scanf("%s", string) is equivalent to scanf("%s", &string[0]). On the other hand, scanf("%s", &string) passes a pointer-to-char[256], but it points to the same place.
Then scanf, when processing the tail of its argument list, will try to pull out a char *. That's the Right Thing when you've passed in string or &string[0], but when you've passed in &string you're depending on something that the language standard doesn't guarantee, namely that the pointers &string and &string[0] -- pointers to objects of different types and sizes that start at the same place -- are represented the same way.
Ref : https://bit.ly/3pdEk6f
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