w3resource

PHP: floatval() function

Description

The floatval() function is used to convert a value to a float.

Version:

(PHP 4 and above)

Syntax:

floatval (var1)

Parameter:

Name Description Required /
Optional		 Type
var1 May be any scalar type. You cannot use floatval() on arrays or objects. Required Mixed*

*Mixed : Mixed indicates that a parameter may accept multiple (but not necessarily all) types.

Return value:

The float value of the given variable.

Value Type: Float.

Example :

?php
$var_name1="122.00,50";
$var_name2="122.00";
$var_name3="122.50";
$var_name4="122,50";
$var_name5="122 50";
$var_name6="0.50";
$var_name7="0,50";
$var_name8="-122.50";
$var_name9="-122,50";
$var_name10="-122 50";
echo floatval($var_name1)."<br>";
echo floatval($var_name2)."<br>";
echo floatval($var_name3)."<br>";
echo floatval($var_name4)."<br>";
echo floatval($var_name5)."<br>";
echo floatval($var_name6)."<br>";
echo floatval($var_name7)."<br>";
echo floatval($var_name8)."<br>";
echo floatval($var_name9)."<br>";
echo floatval($var_name10)."<br>";
?>

Output:

122
122
122.5
122
122
0.5
0
-122.5
-122
-122

View the example in the browser

Practice here online :

See also

PHP Function Reference

Previous: empty
Next: get_defined_vars



PHP: Tips of the Day

SQL injection that gets around mysql_real_escape_string()

Consider the following query:

$iId = mysql_real_escape_string("1 OR 1=1");    
$sSql = "SELECT * FROM table WHERE id = $iId";

mysql_real_escape_string() will not protect you against this. The fact that you use single quotes (' ') around your variables inside your query is what protects you against this. The following is also an option:

$iId = (int)"1 OR 1=1";
$sSql = "SELECT * FROM table WHERE id = $iId";

Ref : https://bit.ly/32q3bJ7