PHP: is_resource() function
Description
The is_resource () function is used to find whether a variable is a resource or not.
Version:
(PHP 4 and above)
Syntax:
is_resource(var_name)
Parameter:
Name | Description | Required / Optional |
Type |
---|---|---|---|
var_name | The variable being checked | Required | Mixed* |
*Mixed: Mixed indicates that a parameter may accept multiple (but not necessarily all) types.
Return value:
TRUE if var is a resource, FALSE otherwise.
Value Type: Boolean.
Example :
<?php
$fh = fopen('demo.txt','r');
if (is_resource($fh))
{
echo "File is open successfully......";
}
else
echo "wrong way to open a file";
?>
Output:
File is open successfully......
View the example in the browser
See also
PHP: Tips of the Day
Returns true if the given string is a palindrome, false otherwise
Example:
<?php function tips_palindrome($string) { return strrev($string) === (string) $string; } print(tips_palindrome('malayalam')); print("\n"); print(tips_palindrome(151)); ?>
Output:
1 1
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