PHP: is_resource() function

Description

The is_resource () function is used to find whether a variable is a resource or not.

Version:

(PHP 4 and above)

Syntax:

is_resource(var_name)

Parameter:

*Mixed: Mixed indicates that a parameter may accept multiple (but not necessarily all) types.

Return value:

TRUE if var is a resource, FALSE otherwise.

Value Type: Boolean.

Example :

<?php
$fh = fopen('demo.txt','r');
if (is_resource($fh)) 
{
echo "File is open successfully......";
}
else
echo "wrong way to open a file";
?>

Output:

File is open successfully......

View the example in the browser

See also

PHP Function Reference

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