PHP: is_resource() function
Description
The is_resource () function is used to find whether a variable is a resource or not.
Version:
(PHP 4 and above)
Syntax:
is_resource(var_name)
Parameter:
| Name | Description | Required / Optional |
Type |
|---|---|---|---|
| var_name | The variable being checked | Required | Mixed* |
*Mixed: Mixed indicates that a parameter may accept multiple (but not necessarily all) types.
Return value:
TRUE if var is a resource, FALSE otherwise.
Value Type: Boolean.
Example :
<?php
$fh = fopen('demo.txt','r');
if (is_resource($fh))
{
echo "File is open successfully......";
}
else
echo "wrong way to open a file";
?>
Output:
File is open successfully......
View the example in the browser
See also
New Content: Composer: Dependency manager for PHP, R Programming