w3resource

PHP: is_long() function

Description

The is_long() function is used to test whether the type of the specified variable is an integer or not. The function is an alias of is_int().

Version:

(PHP 4 and above)

Syntax:

is_long(var_name)

Parameter:

Name Description Required /
Optional
Type
var_name The variable being checked Required Mixed*

*Mixed: Mixed indicates that a parameter may accept multiple (but not necessarily all) types.

Return value:

TRUE if var_name is an integer, FALSE otherwise.

Value Type: Boolean

Example:

<?php
$var_name1=678;
$var_name2="a678";
$var_name3="678";
$var_name4=999;
$var_name5=698.99;
$var_name6=array("a1","a2");
$var_name7=+125689.66;
if (is_long($var_name1))
{
echo "$var_name1 is long number.<br>" ;
}
else
{
echo "$var_name1 is not an long number.<br>" ;
}
if (is_long($var_name2))
{
echo "$var_name2 is long number.<br>" ;
}
else
{
echo "$var_name2 is not long number.<br>" ;
}
$result=is_long($var_name3);
echo "[ $var_name3 is long number? ]" .var_dump($result)."<br>";
$result=is_long($var_name4);
echo "[ $var_name4 is long number? ]" .var_dump($result)."<br>";
$result=is_long($var_name5);
echo "[ $var_name5 is long number? ]" .var_dump($result)."<br>";
$result=is_long($var_name6);
echo "[ $var_name6 is long number? ]" .var_dump($result)."<br>";
$result=is_long($var_name7);
echo "[ $var_name7 is long number? ]" .var_dump($result);
?>        

Output:

678 is long number.
a678 is not long number.
bool(false)  [ 678 is long number? ]
bool(true)  [ 999 is long number? ]
bool(false)  [ 698.99 is long number? ]
bool(false)  [ Array is long number? ]
bool(false)  [ 125689.66 is long number? ]

View the example in the browser

Practice here online :

See also

PHP Function Reference

Previous: is_integer
Next: is_null



PHP: Tips of the Day

SQL injection that gets around mysql_real_escape_string()

Consider the following query:

$iId = mysql_real_escape_string("1 OR 1=1");    
$sSql = "SELECT * FROM table WHERE id = $iId";

mysql_real_escape_string() will not protect you against this. The fact that you use single quotes (' ') around your variables inside your query is what protects you against this. The following is also an option:

$iId = (int)"1 OR 1=1";
$sSql = "SELECT * FROM table WHERE id = $iId";

Ref : https://bit.ly/32q3bJ7