C free() function
C free() function - Free allocated memory
Syntax:
void free(void *ptr)
The free() function is used to free a block of storage. The ptr argument points to a block that is previously reserved with a call to the calloc(), malloc(), realloc().
Parameters:
Name | Description | Required /Optional |
---|---|---|
ptr | Previously allocated memory block to be freed. | Required |
Return value from free()
- There is no return value.
Example: free() function
The following example shows the usage of free() function.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main () {
char *str;
/* Initial memory allocation */
str = (char *) malloc(10);
strcpy(str, "w3resource");
printf("String = %s, Address = %u\n", str, str);
/* Deallocate allocated memory */
free(str);
return(0);
}
Output:
String = w3resource, Address = 7738336
C Programming Code Editor:
Previous C Programming: C calloc()
Next C Programming: C malloc()
C Programming: Tips of the Day
What's the point of const pointers?
const is a tool which you should use in pursuit of a very important C++ concept:
Find bugs at compile-time, rather than run-time, by getting the compiler to enforce what you mean.
Even though it does not change the functionality, adding const generates a compiler error when you're doing things you didn't mean to do. Imagine the following typo:
void foo(int* ptr) { ptr = 0;// oops, I meant *ptr = 0 }
If you use int* const, this would generate a compiler error because you're changing the value to ptr. Adding restrictions via syntax is a good thing in general. Just don't take it too far -- the example you gave is a case where most people don't bother using const.
Ref : https://bit.ly/33Cdn3Q
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