C wctomb() function
C wctomb() function - Convert a wide-character code to a character
Syntax wctomb() function
int wctomb(char *str, wchar_t wchar)
The wctomb() function is used to convert the wchar_t value of character into a multibyte array pointed to by string. The function is left in the initial shift state if the value of the character is 0.
Parameters wctomb() function
Name | Description | Required /Optional |
---|---|---|
str | The address of a multibyte character. | Required |
wchar | A wide character. | Required |
Return value from wctomb()
- If wctomb converts the wide character to a multibyte character, it returns the number of bytes in the wide character.
- If wchar is the wide-character null character (L'\0'), wctomb returns 1.
- If the target pointer mbchar is NULL, wctomb returns 0.
- If the conversion isn't possible in the current locale, wctomb returns -1.
Example: wctomb() function
The following example shows the usage of wctomb() function.
#include <stdio.h>
#include <stdlib.h>
#include <wchar.h>
#define SIZE 40
int main(void)
{
static char buffer[ SIZE ];
wchar_t wch = L'd';
int length;
length = wctomb( buffer, wch );
printf( "The number of bytes that comprise the multibyte "
"character is %i\n", length );
printf( "And the converted string is \"%s\"\n", buffer );
}
Output:
The number of bytes that comprise the multibyte character is 1 And the converted string is "d"
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