C malloc() function
C malloc() function - A memory allocator
The malloc() function is used to reserve a block of storage of size bytes. Unlike the calloc() function, malloc() does not initialize all elements to 0.
Syntax malloc() function
void *malloc(size_t size)
Parameters malloc() function
Name | Description | Required /Optional |
---|---|---|
size | Bytes to allocate. | Required |
Return value from malloc()
- Returns a pointer to the reserved space.
- NULL if not enough storage is available, or if size was specified as zero.
Example: malloc() function
The following example shows the usage of malloc() function.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main () {
char *str;
/* Initial memory allocation */
str = (char *) malloc(10);
strcpy(str, "w3resource.com");
printf("String = %s, Address = %u\n", str, str);
/* Deallocate allocated memory */
free(str);
return(0);
}
Output:
String = w3resource.com, Address = 1905632
C Programming Code Editor:
Previous C Programming: C free()
Next C Programming: C realloc()
C Programming: Tips of the Day
What's the point of const pointers?
const is a tool which you should use in pursuit of a very important C++ concept:
Find bugs at compile-time, rather than run-time, by getting the compiler to enforce what you mean.
Even though it does not change the functionality, adding const generates a compiler error when you're doing things you didn't mean to do. Imagine the following typo:
void foo(int* ptr) { ptr = 0;// oops, I meant *ptr = 0 }
If you use int* const, this would generate a compiler error because you're changing the value to ptr. Adding restrictions via syntax is a good thing in general. Just don't take it too far -- the example you gave is a case where most people don't bother using const.
Ref : https://bit.ly/33Cdn3Q
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