C isgraph() function
C isgraph(int ch)
The isgraph() function is used to check whether a character is a graphic character or not. The function is defined in the ctype.h header file.
Note: In ISO/IEC 646 and related standards including ISO 8859 and Unicode, a graphic character is any character intended to be written, printed, or otherwise displayed in a form that can be read by humans. In other words, it is any encoded character that is associated with one or more glyphs
Syntax:
int isgraph(int argument);
isgraph() Parameters:
Name | Description | Required /Optional |
---|---|---|
ch | ch is a character of class graph in the current locale. | Required |
Return value from isgraph()
- The isgraph() function returns non-zero if ch is a character with a visible representation; otherwise, returns 0.
Example-1: Check graphic character
#include <stdio.h>
#include <ctype.h>
int main()
{
char ch;
ch = ' ';
printf("\nIf %c is graph character or not? %d", ch, isgraph(ch));
ch = '\n';
printf("\nIf %c is graph character or not? %d", ch, isgraph(ch));
ch = '5';
printf("\nIf %c is graph character or not? %d", ch, isgraph(ch));
}
Output:
If is graph character or not? 0 If is graph character or not? 0 If 5 is graph character or not? 4
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C Programming: Tips of the Day
Reading a string with scanf :
An array "decays" into a pointer to its first element, so scanf("%s", string) is equivalent to scanf("%s", &string[0]). On the other hand, scanf("%s", &string) passes a pointer-to-char[256], but it points to the same place.
Then scanf, when processing the tail of its argument list, will try to pull out a char *. That's the Right Thing when you've passed in string or &string[0], but when you've passed in &string you're depending on something that the language standard doesn't guarantee, namely that the pointers &string and &string[0] -- pointers to objects of different types and sizes that start at the same place -- are represented the same way.
Ref : https://bit.ly/3pdEk6f
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