C isxdigit() function
C isxdigit(int ch)
The isxdigit() function is used to check whether a character is a hexadecimal digit character (0-9, a-f, A-F) or not. The function is defined in the ctype.h header file.
Syntax:
int isxdigit( int arg );
isxdigit() Parameters:
Name | Description | Required /Optional |
---|---|---|
ch | Argument ch represents a uppercase letter. | Required |
Return value from isxdigit()
- The isxdigit() returns non-zero if ch is a hexadecimal digit; otherwise returns 0.
Example-1: C isxdigit() function
#include <stdio.h>
#include <ctype.h>
int main() {
char ch;
int result;
printf("Check whether a character is a hexadecimal digit character or not!\n");
ch = 'a';
result = isxdigit(ch);
printf("\nReturn value is %d When %c is passed as an argemdent.", result, ch);
ch = 'g';
result = isxdigit(ch);
printf("\nReturn value is %d When %c is passed as an argemdent.", result, ch);
ch = 'i';
result = isxdigit(ch);
printf("\nReturn value is %d When %c is passed as an argemdent.", result, ch);
ch = '0';
result = isxdigit(ch);
printf("\nReturn value is %d When %c is passed as an argemdent.", result, ch);
return 0;
}
Output:
Check whether a character is a hexadecimal digit character or not! Return value is 128 When a is passed as an argemdent. Return value is 0 When g is passed as an argemdent. Return value is 0 When i is passed as an argemdent. Return value is 128 When 0 is passed as an argemdent.
Example-2: Program to Check Hexadecimal Character
#include <stdio.h>
#include <ctype.h>
int main() {
char ch;
printf("Input a character: ");
ch = getchar();
if (isxdigit(ch) != 0)
{
printf("%c is a hexadecimal character.", ch);
}
else
{
printf("%c is not a hexadecimal character.", ch);
}
return 0;
}
Output:
Input a character: b b is a hexadecimal character.
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C Programming: Tips of the Day
Reading a string with scanf :
An array "decays" into a pointer to its first element, so scanf("%s", string) is equivalent to scanf("%s", &string[0]). On the other hand, scanf("%s", &string) passes a pointer-to-char[256], but it points to the same place.
Then scanf, when processing the tail of its argument list, will try to pull out a char *. That's the Right Thing when you've passed in string or &string[0], but when you've passed in &string you're depending on something that the language standard doesn't guarantee, namely that the pointers &string and &string[0] -- pointers to objects of different types and sizes that start at the same place -- are represented the same way.
Ref : https://bit.ly/3pdEk6f
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