C tolower() function
C tolower(int c)
The tolower() function is used to translate uppercase characters to lowercase characters. The function is defined in the ctype.h header file.
Syntax:
int tolower(int argument);
tolower() Parameters:
Name | Description | Required /Optional |
---|---|---|
ch | Argument ch represents a uppercase letter. | Required |
Return value from tolower()
- Upon successful completion, tolower() returns the lowercase letter corresponding to the argument passed; otherwise returns the argument unchanged.
Example: How tolower() function works?
#include <stdio.h>
#include <ctype.h>
int main() {
char ch;
printf("Convert upper case to lower case:\n");
ch = 'W';
printf("%c -> %c", ch, tolower(ch));
ch = 'x';
printf("\n%c -> %c", ch, tolower(ch));
ch = 'Y';
printf("\n%c -> %c", ch, tolower(ch));
ch = 'A';
printf("\n%c -> %c", ch, tolower(ch));
return 0;
}
Output:
Convert upper case to lower case: W -> w x -> x Y -> y A -> a
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C Programming: Tips of the Day
Reading a string with scanf :
An array "decays" into a pointer to its first element, so scanf("%s", string) is equivalent to scanf("%s", &string[0]). On the other hand, scanf("%s", &string) passes a pointer-to-char[256], but it points to the same place.
Then scanf, when processing the tail of its argument list, will try to pull out a char *. That's the Right Thing when you've passed in string or &string[0], but when you've passed in &string you're depending on something that the language standard doesn't guarantee, namely that the pointers &string and &string[0] -- pointers to objects of different types and sizes that start at the same place -- are represented the same way.
Ref : https://bit.ly/3pdEk6f
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