C ispunct() function
C ispunct(int ch)
The ispunct() function is used to check whether a character is a punctuation mark or not. The function is defined in the ctype.h header file.
Syntax:
int ispunct(int argument);
ispunct() Parameters:
Name | Description | Required /Optional |
---|---|---|
ch | ch is a character of class punct in the current locale. | Required |
Return value from ispunct()
- The ispunct() function returns non-zero if ch is a punctuation character; otherwise, returns 0.
Example-1: Program to check punctuation
#include <stdio.h>
#include <ctype.h>
int main()
{
char ch;
ch = ':';
printf("\nIf %c is punctuation character or not? %d", ch, ispunct(ch));
ch = ',';
printf("\nIf %c is punctuation character or not? %d", ch, ispunct(ch));
ch = 'A';
printf("\nIf %c is punctuation character or not? %d", ch, ispunct(ch));
return 0;
}
Output:
If : is punctuation character or not? 16 If , is punctuation character or not? 16 If A is punctuation character or not? 0
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C Programming: Tips of the Day
Reading a string with scanf :
An array "decays" into a pointer to its first element, so scanf("%s", string) is equivalent to scanf("%s", &string[0]). On the other hand, scanf("%s", &string) passes a pointer-to-char[256], but it points to the same place.
Then scanf, when processing the tail of its argument list, will try to pull out a char *. That's the Right Thing when you've passed in string or &string[0], but when you've passed in &string you're depending on something that the language standard doesn't guarantee, namely that the pointers &string and &string[0] -- pointers to objects of different types and sizes that start at the same place -- are represented the same way.
Ref : https://bit.ly/3pdEk6f
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