w3resource

C isprint() function

C isprint(int ch)

The isprint() function is used to check whether a character is a printable character or not. The function is defined in the ctype.h header file.

Syntax:

int isprint( int arg );

isprint() Parameters:

Name Description Required /Optional
ch ch is a character of class upper in the current locale. Required

Return value from isprint()

  • The isprint() function returns non-zero if ch is a printable character; otherwise returns 0.

Example: C isprint() function

#include <stdio.h>
#include <ctype.h>
int main()
{
    char ch;
    ch = 'y';
    printf("\nIf %c is printable character or not? %d", ch, isprint(ch));
    ch = '\t';
    printf("\nIf %c is printable character or not? %d", ch, isprint(ch));
    ch = 'A';
    printf("\nIf %c is printable character or not? %d", ch, isprint(ch));
}

Output:

If y is printable character or not? 2
If       is printable character or not? 0
If A is printable character or not? 1

C Programming Code Editor:

Contribute your code and comments through Disqus.

Previous C Programming: C islower()
Next C Programming: C ispunct()



Follow us on Facebook and Twitter for latest update.

C Programming: Tips of the Day

Reading a string with scanf :

An array "decays" into a pointer to its first element, so scanf("%s", string) is equivalent to scanf("%s", &string[0]). On the other hand, scanf("%s", &string) passes a pointer-to-char[256], but it points to the same place.

Then scanf, when processing the tail of its argument list, will try to pull out a char *. That's the Right Thing when you've passed in string or &string[0], but when you've passed in &string you're depending on something that the language standard doesn't guarantee, namely that the pointers &string and &string[0] -- pointers to objects of different types and sizes that start at the same place -- are represented the same way.

Ref : https://bit.ly/3pdEk6f