SQL Exercises, Practice, Solution - exercises on employee Database
SQL employee Database [115 Exercise with Solution]
[An editor is available at the bottom of the page to write and execute the scripts.]
Structure of employee Database:
1. From the following table return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+-----------+------------+------------+---------+------------+-------- 68319 | KAYLING | PRESIDENT | | 1991-11-18 | 6000.00 | | 1001 66928 | BLAZE | MANAGER | 68319 | 1991-05-01 | 2750.00 | | 3001 67832 | CLARE | MANAGER | 68319 | 1991-06-09 | 2550.00 | | 1001 65646 | JONAS | MANAGER | 68319 | 1991-04-02 | 2957.00 | | 2001 ....
2. From the following table, write a SQL query to find the salaries of all employees. Return salary. Go to the editor
Sample table: employees
Sample Output:
salary --------- 6000.00 2750.00 2550.00 2957.00 ....
3. From the following table, write a SQL query to find the unique designations of the employees. Return job name. Go to the editor
Sample table: employees
Sample Output:
job_name ----------- CLERK SALESMAN MANAGER PRESIDENT ANALYST (5 rows)
4. From the following table, write a SQL query to list the employees’ name, increased their salary by 15%, and expressed as number of Dollars. Go to the editor
Sample table: employees
Sample Output:
emp_name | Salary ----------+---------- KAYLING | $ 6,900 BLAZE | $ 3,163 CLARE | $ 2,933 JONAS | $ 3,401 SCARLET | $ 3,565 ....
5. From the following table, write a SQL query to list the employee's name and job name as a format of "Employee & Job". Go to the editor
Sample table: employees
Sample Output:
Employee & Job --------------------- KAYLING PRESIDENT BLAZE MANAGER CLARE MANAGER JONAS MANAGER SCARLET ANALYST ....
6. Write a query in SQL to produce the output of employees as follows. Go to the editor
Employee
JONAS(manager).
Sample table: employees
Sample Output:
Employee -------------------- KAYLING(president) BLAZE(manager) CLARE(manager) JONAS(manager) SCARLET(analyst) ....
7. From the following table, write a SQL query to find those employees with hire date in the format like February 22, 1991. Return employee ID, employee name, salary, hire date. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | salary | to_char --------+----------+---------+------------------- 68319 | KAYLING | 6000.00 | NOVEMBER 18,1991 66928 | BLAZE | 2750.00 | MAY 01,1991 67832 | CLARE | 2550.00 | JUNE 09,1991 65646 | JONAS | 2957.00 | APRIL 02,1991 67858 | SCARLET | 3100.00 | APRIL 19,1997 ....
8. From the following table, write a SQL query to count the number of characters except the spaces for each employee name. Return employee name length. Go to the editor
Sample table: employees
Sample Output:
length
--------
7
5
5
5
7
....
9. From the following table, write a SQL query to find the employee ID, salary, and commission of all the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | salary | commission --------+---------+------------ 68319 | 6000.00 | 66928 | 2750.00 | 67832 | 2550.00 | 65646 | 2957.00 | 67858 | 3100.00 | ....
10. From the following table, write a SQL query to find the unique department with jobs. Return department ID, Job name. Go to the editor
Sample table: employees
Sample Output:
dep_id | job_name --------+----------- 3001 | MANAGER 2001 | ANALYST 3001 | SALESMAN 1001 | MANAGER 1001 | PRESIDENT ...
11. From the following table, write a SQL query to find those employees who do not belong to the department 2001. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+-----------+------------+------------+---------+------------+-------- 68319 | KAYLING | PRESIDENT | | 1991-11-18 | 6000.00 | | 1001 66928 | BLAZE | MANAGER | 68319 | 1991-05-01 | 2750.00 | | 3001 67832 | CLARE | MANAGER | 68319 | 1991-06-09 | 2550.00 | | 1001 64989 | ADELYN | SALESMAN | 66928 | 1991-02-20 | 1700.00 | 400.00 | 3001 ....
12. From the following table, write a SQL query to find those employees who joined before 1991. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+----------+------------+------------+--------+------------+-------- 63679 | SANDRINE | CLERK | 69062 | 1990-12-18 | 900.00 | | 2001 (1 row)
13. From the following table, write a SQL query to calculate the average salary of employees who work as analysts. Return average salary. Go to the editor
Sample table: employees
Sample Output:
avg ----------------------- 3100.0000000000000000 (1 row)
14. From the following table, write a SQL query to find the details of the employee ‘BLAZE’. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+----------+------------+------------+---------+------------+-------- 66928 | BLAZE | MANAGER | 68319 | 1991-05-01 | 2750.00 | | 3001 (1 row)
15. From the following table, write a SQL query to identify employees whose commissions exceed their salaries. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+----------+------------+------------+---------+------------+-------- 66564 | MADDEN | SALESMAN | 66928 | 1991-09-28 | 1350.00 | 1500.00 | 3001 (1 row)
16. From the following table, write a SQL query to identify those employees whose salaries exceed 3000 after receiving a 25% salary increase. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+-----------+------------+------------+---------+------------+-------- 68319 | KAYLING | PRESIDENT | | 1991-11-18 | 6000.00 | | 1001 66928 | BLAZE | MANAGER | 68319 | 1991-05-01 | 2750.00 | | 3001 67832 | CLARE | MANAGER | 68319 | 1991-06-09 | 2550.00 | | 1001 65646 | JONAS | MANAGER | 68319 | 1991-04-02 | 2957.00 | | 2001 ....
17. From the following table, write a SQL query to find the names of the employees whose length is six. Return employee name. Go to the editor
Sample table: employees
Sample Output:
emp_name ---------- ADELYN MADDEN TUCKER ADNRES JULIUS MARKER (6 rows)
18. From the following table, write a SQL query to find out which employees joined in the month of January. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+----------+------------+------------+---------+------------+-------- 69324 | MARKER | CLERK | 67832 | 1992-01-23 | 1400.00 | | 1001 (1 row)
19. From the following table, write a SQL query to separate the names of employees and their managers by the string 'works for'. Go to the editor
Sample table: employees
Sample Output:
?column? -------------------------- BLAZE works for KAYLING CLARE works for KAYLING JONAS works for KAYLING SCARLET works for JONAS FRANK works for JONAS .....
20. From the following table, write a SQL query to find those employees whose designation is ‘CLERK’. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+----------+------------+------------+---------+------------+-------- 63679 | SANDRINE | CLERK | 69062 | 1990-12-18 | 900.00 | | 2001 68736 | ADNRES | CLERK | 67858 | 1997-05-23 | 1200.00 | | 2001 69000 | JULIUS | CLERK | 66928 | 1991-12-03 | 1050.00 | | 3001 69324 | MARKER | CLERK | 67832 | 1992-01-23 | 1400.00 | | 1001 (4 rows)
21. From the following table, write a SQL query to identify employees with more than 27 years of experience. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+----------+------------+------------+---------+------------+-------- 64989 | ADELYN | SALESMAN | 66928 | 1991-02-20 | 1700.00 | 400.00 | 3001 65271 | WADE | SALESMAN | 66928 | 1991-02-22 | 1350.00 | 600.00 | 3001 65679 | SANDRINE | CLERK | 69062 | 1990-12-18 | 900.00 | | 2001 (3 rows)
22. From the following table, write a SQL query to find those employees whose salaries are less than 3500. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+----------+------------+------------+---------+------------+-------- 66928 | BLAZE | MANAGER | 68319 | 1991-05-01 | 2750.00 | | 3001 67832 | CLARE | MANAGER | 68319 | 1991-06-09 | 2550.00 | | 1001 65646 | JONAS | MANAGER | 68319 | 1991-04-02 | 2957.00 | | 2001 67858 | SCARLET | ANALYST | 65646 | 1997-04-19 | 3100.00 | | 2001 ....
23. From the following table, write a SQL query to find the employee whose designation is ‘ANALYST’. Return employee name, job name and salary. Go to the editor
Sample table: employees
Sample Output:
emp_name | job_name | salary ----------+----------+--------- SCARLET | ANALYST | 3100.00 FRANK | ANALYST | 3100.00 (2 rows)
24.From the following table, write a SQL query to identify those employees who joined the company in 1991. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+-----------+------------+------------+---------+------------+-------- 68319 | KAYLING | PRESIDENT | | 1991-11-18 | 6000.00 | | 1001 66928 | BLAZE | MANAGER | 68319 | 1991-05-01 | 2750.00 | | 3001 67832 | CLARE | MANAGER | 68319 | 1991-06-09 | 2550.00 | | 1001 65646 | JONAS | MANAGER | 68319 | 1991-04-02 | 2957.00 | | 2001 ....
25. From the following table, write a SQL query to find those employees who joined before 1st April 1991. Return employee ID, employee name, hire date and salary. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | hire_date | salary --------+----------+------------+--------- 63679 | SANDRINE | 1990-12-18 | 900.00 64989 | ADELYN | 1991-02-20 | 1700.00 65271 | WADE | 1991-02-22 | 1350.00 (3 rows)
26. From the following table, write a SQL query identify the employees who do not report to a manager. Return employee name, job name. Go to the editor
Sample table: employees
Sample Output:
emp_name | job_name --------------+-------------- KAYLING | PRESIDENT
27. From the following table, write a SQL query to find the employees who joined on the 1st of May 1991. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+----------+------------+------------+---------+------------+-------- 66928 | BLAZE | MANAGER | 68319 | 1991-05-01 | 2750.00 | | 3001 (1 row)
28. From the following table, write a SQL query to identify the experience of the employees who work under the manager whose ID number is 68319. Return employee ID, employee name, salary, experience. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | salary | Experience --------+----------+---------+------------------------- 66928 | BLAZE | 2750.00 | 26 years 8 mons 29 days 67832 | CLARE | 2550.00 | 26 years 7 mons 21 days 65646 | JONAS | 2957.00 | 26 years 9 mons 28 days (3 rows)
29. From the following table, write a SQL query to find out which employees earn more than 100 per day as a salary. Return employee ID, employee name, salary, and experience. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | salary | Experience --------+----------+---------+------------------------- 68319 | KAYLING | 6000.00 | 26 years 2 mons 12 days 67858 | SCARLET | 3100.00 | 20 years 9 mons 11 days 69062 | FRANK | 3100.00 | 26 years 1 mon 27 days (3 rows)
30. From the following table, write a SQL query to identify those employees who retired after 31-Dec-99, completing eight years of service. Return employee name. Go to the editor
Sample table: employees
Sample Output:
emp_name -------------- ADNRES MARKER SCARLET (3 rows)
31. From the following table, write a SQL query to identify the employees whose salaries are odd. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+----------+------------+------------+---------+------------+-------- 65646 | JONAS | MANAGER | 68319 | 1991-04-02 | 2957.00 | | 2001 (1 row)
32. From the following table, write a SQL query to identify employees whose salaries contain only three digits. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+-----------+------------+------------+---------+------------+-------- 63679 | SANDRINE | CLERK | 69062 | 1990-12-18 | 900.00 | | 2001
33. From the following table, write a SQL query to find those employees who joined in the month of APRIL. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+----------+------------+------------+---------+------------+-------- 65646 | JONAS | MANAGER | 68319 | 1991-04-02 | 2957.00 | | 2001 67858 | SCARLET | ANALYST | 65646 | 1997-04-19 | 3100.00 | | 2001 (2 rows)
34. From the following table, write a SQL query to find out which employees joined the company before the 19th of the month. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+-----------+------------+------------+---------+------------+-------- 68319 | KAYLING | PRESIDENT | | 1991-11-18 | 6000.00 | | 1001 66928 | BLAZE | MANAGER | 68319 | 1991-05-01 | 2750.00 | | 3001 67832 | CLARE | MANAGER | 68319 | 1991-06-09 | 2550.00 | | 1001 65646 | JONAS | MANAGER | 68319 | 1991-04-02 | 2957.00 | | 2001 ...
35. From the following table, write a SQL query to identify those employees who have been working as a SALESMAN and month portion of the experience is more than 10. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+----------+------------+------------+---------+------------+-------- 64989 | ADELYN | SALESMAN | 66928 | 1991-02-20 | 1700.00 | 400.00 | 3001 65271 | WADE | SALESMAN | 66928 | 1991-02-22 | 1350.00 | 600.00 | 3001 (2 rows)
36. From the following table, write a SQL query to find those employees of department id 3001 or 1001 and joined in the year 1991. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+-----------+------------+------------+---------+------------+-------- 68319 | KAYLING | PRESIDENT | | 1991-11-18 | 6000.00 | | 1001 66928 | BLAZE | MANAGER | 68319 | 1991-05-01 | 2750.00 | | 3001 67832 | CLARE | MANAGER | 68319 | 1991-06-09 | 2550.00 | | 1001 64989 | ADELYN | SALESMAN | 66928 | 1991-02-20 | 1700.00 | 400.00 | 3001 ....
37. From the following table, write a SQL query to find the employees who are working for the department ID 1001 or 2001. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+-----------+------------+------------+---------+------------+-------- 68319 | KAYLING | PRESIDENT | | 1991-11-18 | 6000.00 | | 1001 67832 | CLARE | MANAGER | 68319 | 1991-06-09 | 2550.00 | | 1001 65646 | JONAS | MANAGER | 68319 | 1991-04-02 | 2957.00 | | 2001 67858 | SCARLET | ANALYST | 65646 | 1997-04-19 | 3100.00 | | 2001 ....
38. From the following table, write a SQL query to find those employees whose designation is ‘CLERK’ and work in the department ID 2001. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+----------+------------+------------+---------+------------+-------- 63679 | SANDRINE | CLERK | 69062 | 1990-12-18 | 900.00 | | 2001 68736 | ADNRES | CLERK | 67858 | 1997-05-23 | 1200.00 | | 2001 (2 rows)
39. From the following table, write a query in SQL to find those employees where - Go to the editor
1. the employees receive some commission which should not be more than the salary and annual salary including commission is below 34000.
2. Designation is ‘SALESMAN’ and working in the department ‘3001’.
Return employee ID, employee name, salary and job name.
Sample table: employees
Sample Output:
emp_id | emp_name | salary | job_name --------+----------+---------+---------- 64989 | ADELYN | 1700.00 | SALESMAN 65271 | WADE | 1350.00 | SALESMAN 68454 | TUCKER | 1600.00 | SALESMAN (3 rows)
40. From the following table, write a SQL query to find those employees who are either CLERK or MANAGER. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+----------+------------+------------+---------+------------+-------- 66928 | BLAZE | MANAGER | 68319 | 1991-05-01 | 2750.00 | | 3001 67832 | CLARE | MANAGER | 68319 | 1991-06-09 | 2550.00 | | 1001 65646 | JONAS | MANAGER | 68319 | 1991-04-02 | 2957.00 | | 2001 63679 | SANDRINE | CLERK | 69062 | 1990-12-18 | 900.00 | | 2001 ....
41. From the following table, write a SQL query to identify those employees who joined in any month other than February. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+-----------+------------+------------+---------+------------+-------- 68319 | KAYLING | PRESIDENT | | 1991-11-18 | 6000.00 | | 1001 66928 | BLAZE | MANAGER | 68319 | 1991-05-01 | 2750.00 | | 3001 67832 | CLARE | MANAGER | 68319 | 1991-06-09 | 2550.00 | | 1001 65646 | JONAS | MANAGER | 68319 | 1991-04-02 | 2957.00 | | 2001 ....
42. From the following table, write a SQL query to find those employees who joined in the year 1991. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+-----------+------------+------------+---------+------------+-------- 68319 | KAYLING | PRESIDENT | | 1991-11-18 | 6000.00 | | 1001 66928 | BLAZE | MANAGER | 68319 | 1991-05-01 | 2750.00 | | 3001 67832 | CLARE | MANAGER | 68319 | 1991-06-09 | 2550.00 | | 1001 65646 | JONAS | MANAGER | 68319 | 1991-04-02 | 2957.00 | | 2001 ....
43. From the following table, write a SQL query to identify the employees who joined the company in June 1991. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+----------+------------+------------+---------+------------+-------- 67832 | CLARE | MANAGER | 68319 | 1991-06-09 | 2550.00 | | 1001 (1 row)
44. From the following table, write a SQL query to search for all employees with an annual salary between 24000 and 50000 (Begin and end values are included.). Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+----------+------------+------------+---------+------------+-------- 66928 | BLAZE | MANAGER | 68319 | 1991-05-01 | 2750.00 | | 3001 67832 | CLARE | MANAGER | 68319 | 1991-06-09 | 2550.00 | | 1001 65646 | JONAS | MANAGER | 68319 | 1991-04-02 | 2957.00 | | 2001 67858 | SCARLET | ANALYST | 65646 | 1997-04-19 | 3100.00 | | 2001 69062 | FRANK | ANALYST | 65646 | 1991-12-03 | 3100.00 | | 2001 (5 rows)
45. From the following table, write a SQL query to identify all employees who joined the company on 1st May, 20th February, and 3rd December 1991. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id |emp_name |job_name |manager_id |hire_date |salary |commission |dep_id | -------|---------|---------|-----------|-----------|--------|-----------|-------| 66928 |BLAZE |MANAGER |68319 |1991-05-01 |2750.00 | |3001 | 64989 |ADELYN |SALESMAN |66928 |1991-02-20 |1700.00 |400.00 |3001 | 69000 |JULIUS |CLERK |66928 |1991-12-03 |1050.00 | |3001 | 69062 |FRANK |ANALYST |65646 |1991-12-03 |3100.00 | |2001 |
46. From the following table, write a SQL query to find out which employees are working under the managers 63679, 68319, 66564, or 69000. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+----------+------------+------------+---------+------------+-------- 66928 | BLAZE | MANAGER | 68319 | 1991-05-01 | 2750.00 | | 3001 67832 | CLARE | MANAGER | 68319 | 1991-06-09 | 2550.00 | | 1001 65646 | JONAS | MANAGER | 68319 | 1991-04-02 | 2957.00 | | 2001 (3 rows)
47. From the following table, write a SQL query to find which employees joined the company after the month of June in 1991 and within this year. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+-----------+------------+------------+---------+------------+-------- 68319 | KAYLING | PRESIDENT | | 1991-11-18 | 6000.00 | | 1001 69062 | FRANK | ANALYST | 65646 | 1991-12-03 | 3100.00 | | 2001 66564 | MADDEN | SALESMAN | 66928 | 1991-09-28 | 1350.00 | 1500.00 | 3001 68454 | TUCKER | SALESMAN | 66928 | 1991-09-08 | 1600.00 | 0.00 | 3001 69000 | JULIUS | CLERK | 66928 | 1991-12-03 | 1050.00 | | 3001 (5 rows)
48. From the following table, write a SQL query to find those employees who joined in 90's. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+-----------+------------+------------+---------+------------+-------- 68319 | KAYLING | PRESIDENT | | 1991-11-18 | 6000.00 | | 1001 66928 | BLAZE | MANAGER | 68319 | 1991-05-01 | 2750.00 | | 3001 67832 | CLARE | MANAGER | 68319 | 1991-06-09 | 2550.00 | | 1001 65646 | JONAS | MANAGER | 68319 | 1991-04-02 | 2957.00 | | 2001 67858 | SCARLET | ANALYST | 65646 | 1997-04-19 | 3100.00 | | 2001 .....
49. From the following table, write a SQL query to find those managers who are in the department 1001 or 2001. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+----------+------------+------------+---------+------------+-------- 67832 | CLARE | MANAGER | 68319 | 1991-06-09 | 2550.00 | | 1001 65646 | JONAS | MANAGER | 68319 | 1991-04-02 | 2957.00 | | 2001 (2 rows)
50. From the following table, write a SQL query to identify employees who joined in the month of FEBRUARY with a salary range of 1001 to 2000 (Begin and end values are included.). Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+----------+------------+------------+---------+------------+-------- 64989 | ADELYN | SALESMAN | 66928 | 1991-02-20 | 1700.00 | 400.00 | 3001 65271 | WADE | SALESMAN | 66928 | 1991-02-22 | 1350.00 | 600.00 | 3001 (2 rows)
51. From the following table, write a SQL query to find those employees who joined before or after the year 1991. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+----------+------------+------------+---------+------------+-------- 67858 | SCARLET | ANALYST | 65646 | 1997-04-19 | 3100.00 | | 2001 63679 | SANDRINE | CLERK | 69062 | 1990-12-18 | 900.00 | | 2001 68736 | ADNRES | CLERK | 67858 | 1997-05-23 | 1200.00 | | 2001 69324 | MARKER | CLERK | 67832 | 1992-01-23 | 1400.00 | | 1001 (4 rows)
52. From the following table, write a SQL query to find employees along with their department details. Return employee ID, employee name, job name, manager ID, hire date, salary, commission, department ID, and department name. Go to the editor
Sample table: employees
Sample table: department
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id | dep_name --------+----------+-----------+------------+------------+---------+------------+--------+---------- 68319 | KAYLING | PRESIDENT | | 1991-11-18 | 6000.00 | | 1001 | FINANCE 66928 | BLAZE | MANAGER | 68319 | 1991-05-01 | 2750.00 | | 3001 | MARKETING 67832 | CLARE | MANAGER | 68319 | 1991-06-09 | 2550.00 | | 1001 | FINANCE 65646 | JONAS | MANAGER | 68319 | 1991-04-02 | 2957.00 | | 2001 | AUDIT ....
53. From the following table, write a SQL query to identify those employees who earn 60000 or more per year or do not work as ANALYST. Return employee name, job name, (12*salary) as Annual Salary, department ID, and grade. Go to the editor
Sample table: employees
Sample table: department
Sample table: salary_grade
Sample Output:
emp_name | job_name | Annual Salary | dep_id | dep_name | grade ----------+-----------+---------------+--------+-----------+------- SANDRINE | CLERK | 10800.00 | 2001 | AUDIT | 1 ADNRES | CLERK | 14400.00 | 2001 | AUDIT | 1 JULIUS | CLERK | 12600.00 | 3001 | MARKETING | 1 WADE | SALESMAN | 16200.00 | 3001 | MARKETING | 2 MADDEN | SALESMAN | 16200.00 | 3001 | MARKETING | 2 ....
54. From the following table, write a SQL query to identify employees whose salaries are higher than their managers' salaries. Return employee name, job name, manager ID, salary, manager name, manager's salary.. Go to the editor
Sample table: employees
Sample Output:
emp_name | job_name | manager_id | salary | Manager | emp_id | Manager_Salary ----------+----------+------------+---------+---------+--------+---------------- SCARLET | ANALYST | 65646 | 3100.00 | JONAS | 65646 | 2957.00 FRANK | ANALYST | 65646 | 3100.00 | JONAS | 65646 | 2957.00 (2 rows)
55. From the following table, write a SQL query to find those employees whose salary is between 2000 and 5000 (Begin and end values are included.) and location is PERTH. Return employee name, department ID, salary, and commission. Go to the editor
Sample table: employees
Sample table: department
Sample Output:
emp_name | dep_id | salary | commission ----------+--------+---------+------------ BLAZE | 3001 | 2750.00 | (1 row)
56. From the following table, write a SQL query to find the employees whose department ID is 1001 or 3001 and whose salary grade is not 4. They joined the company before 1992-12-31. Return grade, employee name. Go to the editor
Sample table: employees
Sample Output:
grade | emp_name
-------+----------
1 | JULIUS
2 | WADE
2 | MADDEN
2 | MARKER
3 | ADELYN
3 | TUCKER
5 | KAYLING
(7 rows)
Sample table: salary_grade
57. From the following table, write a SQL query to find those employees whose manager name is JONAS. Return employee id, employee name, job name, manager ID, hire date, salary, department ID, employee name. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | dep_id | emp_name --------+----------+----------+------------+------------+---------+--------+---------- 67858 | SCARLET | ANALYST | 65646 | 1997-04-19 | 3100.00 | 2001 | JONAS 69062 | FRANK | ANALYST | 65646 | 1991-12-03 | 3100.00 | 2001 | JONAS (2 rows)
58. From the following table, write a SQL query to find the name and salary of the employee FRANK. Salary should be equal to the maximum salary within his or her salary group. Go to the editor
Sample table: employees
Sample table: salary_grade
Sample Output:
emp_name | salary ----------+--------- FRANK | 3100.00 (1 row)
59. From the following table, write a SQL query to search for employees who are working either as a MANAGER or an ANALYST with a salary between 2000 and 5000 (Begin and end values are included.) without commissions. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+----------+------------+------------+---------+------------+-------- 66928 | BLAZE | MANAGER | 68319 | 1991-05-01 | 2750.00 | | 3001 67832 | CLARE | MANAGER | 68319 | 1991-06-09 | 2550.00 | | 1001 65646 | JONAS | MANAGER | 68319 | 1991-04-02 | 2957.00 | | 2001 67858 | SCARLET | ANALYST | 65646 | 1997-04-19 | 3100.00 | | 2001 69062 | FRANK | ANALYST | 65646 | 1991-12-03 | 3100.00 | | 2001 (5 rows)
60. From the following table, write a SQL query to search for employees working in PERTH or MELBOURNE and month part of their achieved experience is more than 10. Return employee ID, employee name, department ID, salary, and department location. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | dep_id | salary | dep_location --------+----------+--------+---------+-------------- 64989 | ADELYN | 3001 | 1700.00 | PERTH 65271 | WADE | 3001 | 1350.00 | PERTH (2 rows)
Sample table: department
61. From the following table, write a SQL query to find the employees who joined in 1991 and whose department location is SYDNEY or MELBOURNE with a salary range of 2000 to 5000 (Begin and end values are included.). Return employee ID, employee name, department ID, salary, and department location. Go to the editor
Sample table: employees
Sample table: department
Sample Output:
emp_id | emp_name | dep_id | salary | dep_location --------+----------+--------+---------+-------------- 67832 | CLARE | 1001 | 2550.00 | SYDNEY 65646 | JONAS | 2001 | 2957.00 | MELBOURNE 69062 | FRANK | 2001 | 3100.00 | MELBOURNE (3 rows)
62. From the following table, write a SQL query to find the employees of MARKETING department come from MELBOURNE or PERTH, are in grades 3 ,4, and 5 and have at least 25 years of experience. Return department ID, employee ID, employee name, salary, department name, department location and grade. Go to the editor
Sample table: employees
Sample Output:
dep_id |emp_id |emp_name |salary |dep_name |dep_location |grade | -------|-------|---------|--------|----------|-------------|------| 3001 |66928 |BLAZE |2750.00 |MARKETING |PERTH |4 | 3001 |64989 |ADELYN |1700.00 |MARKETING |PERTH |3 | 3001 |68454 |TUCKER |1600.00 |MARKETING |PERTH |3 |
Sample table: salary_grade
Sample table: department
63. From the following table, write a SQL query to find those employees who are senior to their manager. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id | emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+----------+------------+------------+---------+------------+--------+--------+----------+-----------+------------+------------+---------+------------+-------- 66928 | BLAZE | MANAGER | 68319 | 1991-05-01 | 2750.00 | | 3001 | 68319 | KAYLING | PRESIDENT | | 1991-11-18 | 6000.00 | | 1001 67832 | CLARE | MANAGER | 68319 | 1991-06-09 | 2550.00 | | 1001 | 68319 | KAYLING | PRESIDENT | | 1991-11-18 | 6000.00 | | 1001 65646 | JONAS | MANAGER | 68319 | 1991-04-02 | 2957.00 | | 2001 | 68319 | KAYLING | PRESIDENT | | 1991-11-18 | 6000.00 | | 1001 63679 | SANDRINE | CLERK | 69062 | 1990-12-18 | 900.00 | | 2001 | 69062 | FRANK | ANALYST | 65646 | 1991-12-03 | 3100.00 | | 2001 64989 | ADELYN | SALESMAN | 66928 | 1991-02-20 | 1700.00 | 400.00 | 3001 | 66928 | BLAZE | MANAGER | 68319 | 1991-05-01 | 2750.00 | | 3001 65271 | WADE | SALESMAN | 66928 | 1991-02-22 | 1350.00 | 600.00 | 3001 | 66928 | BLAZE | MANAGER | 68319 | 1991-05-01 | 2750.00 | | 3001 (6 rows)
64. From the following tables, write a SQL query to determine which employees have a grade of 4 and a salary between the minimum and maximum. Return all information of each employees and their grade and salary related details. Go to the editor
Sample table: employees
Sample table: salary_grade
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id | grade | min_sal | max_sal --------+----------+----------+------------+------------+---------+------------+--------+-------+---------+--------- 66928 | BLAZE | MANAGER | 68319 | 1991-05-01 | 2750.00 | | 3001 | 4 | 2101 | 3100 67832 | CLARE | MANAGER | 68319 | 1991-06-09 | 2550.00 | | 1001 | 4 | 2101 | 3100 65646 | JONAS | MANAGER | 68319 | 1991-04-02 | 2957.00 | | 2001 | 4 | 2101 | 3100 67858 | SCARLET | ANALYST | 65646 | 1997-04-19 | 3100.00 | | 2001 | 4 | 2101 | 3100 69062 | FRANK | ANALYST | 65646 | 1991-12-03 | 3100.00 | | 2001 | 4 | 2101 | 3100 (5 rows)
65. From the following table, write a SQL query to find those employees who joined after 1991, excluding MARKER or ADELYN in the departments PRODUCTION or AUDIT. Return employee name. Go to the editor
Sample table: employees
Sample table: department
Sample table: salary_grade
Sample Output:
emp_name ---------- ADNRES SCARLET (2 rows)
66. From the following table, write a SQL query to find the employees and their salaries. Sort the result-set in ascending order by salaries. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+-----------+------------+------------+---------+------------+-------- 63679 | SANDRINE | CLERK | 69062 | 1990-12-18 | 900.00 | | 2001 69000 | JULIUS | CLERK | 66928 | 1991-12-03 | 1050.00 | | 3001 68736 | ADNRES | CLERK | 67858 | 1997-05-23 | 1200.00 | | 2001 65271 | WADE | SALESMAN | 66928 | 1991-02-22 | 1350.00 | 600.00 | 3001 ....
67. From the following table, write a SQL query to list employees in ascending order on department ID and descending order on jobs. Return complete information about the employees. Go to the editor
Sample table: employees
68. From the following table, write a SQL query to sort the unique jobs in descending order. Return job name. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+-----------+------------+------------+---------+------------+-------- 68319 | KAYLING | PRESIDENT | | 1991-11-18 | 6000.00 | | 1001 67832 | CLARE | MANAGER | 68319 | 1991-06-09 | 2550.00 | | 1001 69324 | MARKER | CLERK | 67832 | 1992-01-23 | 1400.00 | | 1001 65646 | JONAS | MANAGER | 68319 | 1991-04-02 | 2957.00 | | 2001 ....
69. From the following table, write a SQL query to rank the employees according to their annual salary in ascending order. Return employee ID, employee name, monthly salary, salary/30 as Daily_Salary, and 12*salary as Anual_Salary. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | monthly_salary | daily_salary | anual_salary --------+----------+----------------+----------------------+-------------- 63679 | SANDRINE | 900.00 | 30.0000000000000000 | 10800.00 69000 | JULIUS | 1050.00 | 35.0000000000000000 | 12600.00 68736 | ADNRES | 1200.00 | 40.0000000000000000 | 14400.00 65271 | WADE | 1350.00 | 45.0000000000000000 | 16200.00 66564 | MADDEN | 1350.00 | 45.0000000000000000 | 16200.00 ....
70. From the following table, write a SQL query to find those employees who are either 'CLERK' or 'ANALYST’. Sort the result set in descending order on job_name. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+----------+------------+------------+---------+------------+-------- 63679 | SANDRINE | CLERK | 69062 | 1990-12-18 | 900.00 | | 2001 68736 | ADNRES | CLERK | 67858 | 1997-05-23 | 1200.00 | | 2001 69000 | JULIUS | CLERK | 66928 | 1991-12-03 | 1050.00 | | 3001 69324 | MARKER | CLERK | 67832 | 1992-01-23 | 1400.00 | | 1001 ....
71. From the following table, write a SQL query to find the department location of employee ‘CLARE’. Return department location. Go to the editor
Sample table: employees
Sample Output:
dep_location -------------- SYDNEY (1 row)
Sample table: department
72. From the following table, write a SQL query to find those employees who joined on 1-MAY-91, or 3-DEC-91, or 19-JAN-90. Sort the result-set in ascending order by hire date. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+----------+------------+------------+---------+------------+-------- 66928 | BLAZE | MANAGER | 68319 | 1991-05-01 | 2750.00 | | 3001 69062 | FRANK | ANALYST | 65646 | 1991-12-03 | 3100.00 | | 2001 69000 | JULIUS | CLERK | 66928 | 1991-12-03 | 1050.00 | | 3001 (3 rows)
73. From the following table, write a SQL query to find those employees who earn less than 1000. Sort the result-set in ascending order by salary. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+----------+------------+------------+--------+------------+-------- 63679 | SANDRINE | CLERK | 69062 | 1990-12-18 | 900.00 | | 2001 (1 row)
74. From the following table, write a SQL query to list the employees in ascending order based on salary. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+-----------+------------+------------+---------+------------+-------- 63679 | SANDRINE | CLERK | 69062 | 1990-12-18 | 900.00 | | 2001 69000 | JULIUS | CLERK | 66928 | 1991-12-03 | 1050.00 | | 3001 68736 | ADNRES | CLERK | 67858 | 1997-05-23 | 1200.00 | | 2001 65271 | WADE | SALESMAN | 66928 | 1991-02-22 | 1350.00 | 600.00 | 3001 ....
75. From the following table, write a SQL query to list the employees in the ascending order by job title and in descending order by employee ID. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+-----------+------------+------------+---------+------------+-------- 69062 | FRANK | ANALYST | 65646 | 1991-12-03 | 3100.00 | | 2001 67858 | SCARLET | ANALYST | 65646 | 1997-04-19 | 3100.00 | | 2001 69324 | MARKER | CLERK | 67832 | 1992-01-23 | 1400.00 | | 1001 69000 | JULIUS | CLERK | 66928 | 1991-12-03 | 1050.00 | | 3001 ....
76. From the following table, write a SQL query to list the unique jobs of department 2001 and 3001 in descending order. Return job name. Go to the editor
Sample table: employees
Sample Output:
job_name ---------- SALESMAN MANAGER CLERK ANALYST (4 rows)
77. From the following table, write a SQL query to list all the employees except the PRESIDENT and the MANAGER in ascending order of salaries. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+----------+------------+------------+---------+------------+-------- 63679 | SANDRINE | CLERK | 69062 | 1990-12-18 | 900.00 | | 2001 69000 | JULIUS | CLERK | 66928 | 1991-12-03 | 1050.00 | | 3001 68736 | ADNRES | CLERK | 67858 | 1997-05-23 | 1200.00 | | 2001 66564 | MADDEN | SALESMAN | 66928 | 1991-09-28 | 1350.00 | 1500.00 | 3001 ....
78. From the following table, write a SQL query to find the employees whose annual salary is less than $25,000 per year. Sort the result set in ascending order of the salary. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+----------+------------+------------+---------+------------+-------- 63679 | SANDRINE | CLERK | 69062 | 1990-12-18 | 900.00 | | 2001 69000 | JULIUS | CLERK | 66928 | 1991-12-03 | 1050.00 | | 3001 68736 | ADNRES | CLERK | 67858 | 1997-05-23 | 1200.00 | | 2001 65271 | WADE | SALESMAN | 66928 | 1991-02-22 | 1350.00 | 600.00 | 3001 66564 | MADDEN | SALESMAN | 66928 | 1991-09-28 | 1350.00 | 1500.00 | 3001 ....
79. From the following table, write a SQL query to list the employees who works as a SALESMAN. Sort the result set in ascending order of annual salary. Return employee id, name, annual salary, daily salary of all the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | Annual Salary | Daily Salary --------+----------+---------------+--------------------- 65271 | WADE | 16200.00 | 44.3835616438356164 66564 | MADDEN | 16200.00 | 44.3835616438356164 68454 | TUCKER | 19200.00 | 52.6027397260273973 64989 | ADELYN | 20400.00 | 55.8904109589041096 (4 rows)
80. From the following table, write a SQL query to list the employee ID, name, hire date, current date and experience of the employees in ascending order on their experiences. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | hire_date | date | exp --------+----------+------------+------------+------------------------- 68736 | ADNRES | 1997-05-23 | 2018-02-01 | 20 years 8 mons 9 days 67858 | SCARLET | 1997-04-19 | 2018-02-01 | 20 years 9 mons 12 days 69324 | MARKER | 1992-01-23 | 2018-02-01 | 26 years 9 days 69062 | FRANK | 1991-12-03 | 2018-02-01 | 26 years 1 mon 29 days 69000 | JULIUS | 1991-12-03 | 2018-02-01 | 26 years 1 mon 29 days ....
81. From the following table, write a SQL query to list the employees in ascending order of designations of those joined after the second half of 1991. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+-----------+------------+------------+---------+------------+-------- 69062 | FRANK | ANALYST | 65646 | 1991-12-03 | 3100.00 | | 2001 69000 | JULIUS | CLERK | 66928 | 1991-12-03 | 1050.00 | | 3001 68319 | KAYLING | PRESIDENT | | 1991-11-18 | 6000.00 | | 1001 66564 | MADDEN | SALESMAN | 66928 | 1991-09-28 | 1350.00 | 1500.00 | 3001 68454 | TUCKER | SALESMAN | 66928 | 1991-09-08 | 1600.00 | 0.00 | 3001 (5 rows)
82. From the following table, write a SQL query to find the location of all the employees working in the FINANCE or AUDIT department. Sort the result-set in ascending order by department ID. Return complete information about the employees. Go to the editor
Sample table: employees
Sample table: department
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id | dep_id | dep_name | dep_location --------+----------+-----------+------------+------------+---------+------------+--------+--------+----------+-------------- 68319 | KAYLING | PRESIDENT | | 1991-11-18 | 6000.00 | | 1001 | 1001 | FINANCE | SYDNEY 67832 | CLARE | MANAGER | 68319 | 1991-06-09 | 2550.00 | | 1001 | 1001 | FINANCE | SYDNEY 69324 | MARKER | CLERK | 67832 | 1992-01-23 | 1400.00 | | 1001 | 1001 | FINANCE | SYDNEY 67858 | SCARLET | ANALYST | 65646 | 1997-04-19 | 3100.00 | | 2001 | 2001 | AUDIT | MELBOURNE ....
83. From the following tables, write a SQL query to find the employees along with grades in ascending order. Return complete information about the employees. Go to the editor
Sample table: employees
Sample table: salary_grade
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id | grade | min_sal | max_sal --------+----------+-----------+------------+------------+---------+------------+--------+-------+---------+--------- 63679 | SANDRINE | CLERK | 69062 | 1990-12-18 | 900.00 | | 2001 | 1 | 800 | 1300 68736 | ADNRES | CLERK | 67858 | 1997-05-23 | 1200.00 | | 2001 | 1 | 800 | 1300 69000 | JULIUS | CLERK | 66928 | 1991-12-03 | 1050.00 | | 3001 | 1 | 800 | 1300 65271 | WADE | SALESMAN | 66928 | 1991-02-22 | 1350.00 | 600.00 | 3001 | 2 | 1301 | 1500 ....
84. From the following table, write a SQL query to find the employees according to the department in ascending order. Return name, job name, department, salary, and grade. Go to the editor
Sample table: employees
Sample table: department
Sample table: salary_grade
Sample Output:
emp_name | job_name | dep_name | salary | grade ----------+-----------+-----------+---------+------- KAYLING | PRESIDENT | FINANCE | 6000.00 | 5 CLARE | MANAGER | FINANCE | 2550.00 | 4 MARKER | CLERK | FINANCE | 1400.00 | 2 SANDRINE | CLERK | AUDIT | 900.00 | 1 SCARLET | ANALYST | AUDIT | 3100.00 | 4 ....
85. From the following table, write a SQL query to select all employees except CLERK and sort the results in descending order by salary. Return employee name, job name, salary, grade and department name. Go to the editor
Sample table: employees
Sample table: department
Sample table: salary_grade
Sample Output:
emp_name | job_name | salary | grade | dep_name ----------+-----------+---------+-------+----------- KAYLING | PRESIDENT | 6000.00 | 5 | FINANCE FRANK | ANALYST | 3100.00 | 4 | AUDIT SCARLET | ANALYST | 3100.00 | 4 | AUDIT JONAS | MANAGER | 2957.00 | 4 | AUDIT ....
86. From the following table, write a SQL query to find those employees who work in the department 1001 or 2001. Return employee ID, name, salary, department, grade, experience, and annual salary. Go to the editor
Sample table: employees
Sample table: department
Sample table: salary_grade
87. From the following table, write a SQL query to list the details of the employees along with the details of their departments. Go to the editor
Sample table: employees
Sample table: department
88. From the following table, write a SQL query to list the employees who are senior to their MANAGERS. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id | emp_id | emp_name | job_name | manager_id | hire_date | salary | commission| dep_id --------+----------+----------+------------+------------+---------+------------+--------+--------+----------+-----------+------------+------------+---------+------------+-------- 66928 | BLAZE | MANAGER | 68319 | 1991-05-01 | 2750.00 | | 3001 | 68319 | KAYLING | PRESIDENT | | 1991-11-18 | 6000.00 | | 1001 67832 | CLARE | MANAGER | 68319 | 1991-06-09 | 2550.00 | | 1001 | 68319 | KAYLING | PRESIDENT | | 1991-11-18 | 6000.00 | | 1001 65646 | JONAS | MANAGER | 68319 | 1991-04-02 | 2957.00 | | 2001 | 68319 | KAYLING | PRESIDENT | | 1991-11-18 | 6000.00 | | 1001 63679 | SANDRINE | CLERK | 69062 | 1990-12-18 | 900.00 | | 2001 | 69062 | FRANK | ANALYST | 65646 | 1991-12-03 | 3100.00 | | 2001 ....
89. From the following table, write a SQL query to find those employees who work in the department 1001. Sort the result-set in ascending order by salary. Return employee ID, employee name, salary and department ID. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | salary | dep_id --------+----------+---------+-------- 69324 | MARKER | 1400.00 | 1001 67832 | CLARE | 2550.00 | 1001 68319 | KAYLING | 6000.00 | 1001 (3 rows)
90. From the following table, write a SQL query to find the highest salary. Return highest salary. Go to the editor
Sample table: employees
Sample Output:
max --------- 6000.00 (1 row)
91. From the following table, write a SQL query to calculate the average salary and average total remuneration (salary and commission) for each type of job. Return name, average salary and average total remuneration. Go to the editor
Sample table: employees
Sample Output:
job_name | avg | avg -----------+-----------------------+----------------------- CLERK | 1137.5000000000000000 | SALESMAN | 1500.0000000000000000 | 2125.0000000000000000 MANAGER | 2752.3333333333333333 | PRESIDENT | 6000.0000000000000000 | ANALYST | 3100.0000000000000000 | (5 rows)
92. From the following table, write a SQL query to calculate the total annual salary distributed across each job in 1991. Return job name, total annual salary. Go to the editor
Sample table: employees
Sample Output:
job_name | sum -----------+---------- CLERK | 12600.00 PRESIDENT | 72000.00 SALESMAN | 72000.00 ANALYST | 37200.00 MANAGER | 99084.00 (5 rows)
93. From the following table, write a SQL query to list the employee id, name, department id, location of all the employees. Go to the editor
Sample table: employees
Sample table: department
Sample Output:
emp_id | emp_name | dep_id | dep_location --------+----------+--------+-------------- 68319 | KAYLING | 1001 | SYDNEY 66928 | BLAZE | 3001 | PERTH 67832 | CLARE | 1001 | SYDNEY 65646 | JONAS | 2001 | MELBOURNE 67858 | SCARLET | 2001 | MELBOURNE ....
94. From the following table, write a SQL query to find those employees who work in the department ID 1001 or 2001. Return employee ID, employee name, department ID, department location, and department name. Go to the editor
Sample table: employees
Sample table: department
Sample Output:
emp_id | emp_name | dep_id | dep_location | dep_name --------+----------+--------+--------------+---------- 68319 | KAYLING | 1001 | SYDNEY | FINANCE 67832 | CLARE | 1001 | SYDNEY | FINANCE 65646 | JONAS | 2001 | MELBOURNE | AUDIT 68736 | ADNRES | 2001 | MELBOURNE | AUDIT ....
95. From the following table, write a SQL query to find those employees whose salary is in the range of minimum and maximum salary (Begin and end values are included.). Return employee ID, name, salary and grade. Go to the editor
Sample table: employees
Sample table: salary_grade
Sample Output:
emp_id | emp_name | salary | grade --------+----------+---------+------- 63679 | SANDRINE | 900.00 | 1 68736 | ADNRES | 1200.00 | 1 69000 | JULIUS | 1050.00 | 1 65271 | WADE | 1350.00 | 2 66564 | MADDEN | 1350.00 | 2 ....
96. From the following table, write a SQL query to create a list of the managers and the number of employees they supervise. Sort the result set in ascending order on manager. Return manager ID and number of employees under them. Go to the editor
Sample table: employees
Sample Output:
manager_id | count
------------+-------
65646 | 2
66928 | 5
67832 | 1
67858 | 1
68319 | 3
69062 | 1
(6 rows)
97. From the following table, write a SQL query to count the number of employees in each designation of a department. Return department id, job name and number of employees. Go to the editor
Sample table: employees
Sample Output:
dep_id | job_name | count --------+-----------+------- 3001 | MANAGER | 1 2001 | ANALYST | 2 3001 | SALESMAN | 4 1001 | MANAGER | 1 ....
98. From the following table, write a SQL query to identify the departments in which at least two employees are employed. Return department id, number of employees. Go to the editor
Sample table: employees
Sample Output:
dep_id | count --------+------- 3001 | 6 1001 | 3 2001 | 5 (3 rows)
99. From the following table, write a SQL query to list the grade, number of employees, and maximum salary of each grade. Go to the editor
Sample table: employees
Sample table: salary_grade
Sample Output:
grade | count | max
-------+-------+---------
4 | 5 | 3100.00
1 | 3 | 1200.00
5 | 1 | 6000.00
3 | 2 | 1700.00
2 | 3 | 1400.00
(5 rows)
100. From the following table, write a SQL query to identify departments with at least two SALESMEN in each grade. Return department name, grade and number of employees. Go to the editor
Sample table: employees
Sample table: department
Sample table: salary_grade
Sample Output:
dep_name | grade | count -----------+-------+------- MARKETING | 2 | 2 MARKETING | 3 | 2 (2 rows)
101. From the following table, write a SQL query to identify departments with fewer than four employees. Return department ID, number of employees. Go to the editor
Sample table: employees
Sample Output:
dep_id | count --------+------- 1001 | 3 (1 row)
102. From the following table, write a SQL query to find which departments have at least two employees. Return department name, number of employees. Go to the editor
Sample table: employees
Sample table: department
Sample Output:
dep_name | count -----------+------- FINANCE | 3 MARKETING | 6 AUDIT | 5 (3 rows)s
103. From the following table, write a SQL query to check whether the employees ID are unique or not. Return employee id, number of employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | count --------+------- 69324 | 1 69062 | 1 63679 | 1 67858 | 1 66564 | 1 .....
104. From the following table, write a SQL query to find number of employees and average salary. Group the result set on department id and job name. Return number of employees, average salary, department ID, and job name. Go to the editor
Sample table: employees
Sample Output:
count | avg | dep_id | job_name
-------+-----------------------+--------+-----------
1 | 2750.0000000000000000 | 3001 | MANAGER
2 | 3100.0000000000000000 | 2001 | ANALYST
4 | 1500.0000000000000000 | 3001 | SALESMAN
1 | 2550.0000000000000000 | 1001 | MANAGER
....
105. From the following table, write a SQL query to identify those employees whose names begin with 'A' and are six characters long. Return employee name. Go to the editor
Sample table: employees
Sample Output:
emp_name ---------- ADELYN ADNRES (2 rows)
106. From the following table, write a SQL query to find those employees whose name is six characters in length and the third character must be 'R'. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+----------+------------+------------+---------+------------+-------- 69324 | MARKER | CLERK | 67832 | 1992-01-23 | 1400.00 | | 1001 (1 row)
107. From the following table, write a SQL query to find those employees whose name is six characters in length, starting with 'A' and ending with 'N'. Return number of employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+----------+------------+------------+---------+------------+-------- 64989 | ADELYN | SALESMAN | 66928 | 1991-02-20 | 1700.00 | 400.00 | 3001 (1 row)
108. From the following table, write a SQL query to find those employees who joined in the month of where the second letter is 'a'. Return number of employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+----------+------------+------------+---------+------------+-------- 66928 | BLAZE | MANAGER | 68319 | 1991-05-01 | 2750.00 | | 3001 68736 | ADNRES | CLERK | 67858 | 1997-05-23 | 1200.00 | | 2001 69324 | MARKER | CLERK | 67832 | 1992-01-23 | 1400.00 | | 1001 (3 rows)
109. From the following table, write a SQL query to find those employees whose names contain the character set 'AR' together. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+----------+------------+------------+---------+------------+-------- 67832 | CLARE | MANAGER | 68319 | 1991-06-09 | 2550.00 | | 1001 67858 | SCARLET | ANALYST | 65646 | 1997-04-19 | 3100.00 | | 2001 69324 | MARKER | CLERK | 67832 | 1992-01-23 | 1400.00 | | 1001 (3 rows)
110. From the following table, write a SQL query to find those employees who joined in 90's. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+-----------+------------+------------+---------+------------+-------- 68319 | KAYLING | PRESIDENT | | 1991-11-18 | 6000.00 | | 1001 66928 | BLAZE | MANAGER | 68319 | 1991-05-01 | 2750.00 | | 3001 67832 | CLARE | MANAGER | 68319 | 1991-06-09 | 2550.00 | | 1001 65646 | JONAS | MANAGER | 68319 | 1991-04-02 | 2957.00 | | 2001 ....
111. From the following table, write a SQL query to find those employees whose ID not start with the digit 68. Return employee ID, employee ID using trim function. Go to the editor
Sample table: employees
Sample Output:
emp_id | btrim --------+------- 66928 | 66928 67832 | 67832 65646 | 65646 67858 | 67858 ....
112. From the following table, write a SQL query to find those employees whose names contain the letter 'A’. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+-----------+------------+------------+---------+------------+-------- 68319 | KAYLING | PRESIDENT | | 1991-11-18 | 6000.00 | | 1001 66928 | BLAZE | MANAGER | 68319 | 1991-05-01 | 2750.00 | | 3001 67832 | CLARE | MANAGER | 68319 | 1991-06-09 | 2550.00 | | 1001 65646 | JONAS | MANAGER | 68319 | 1991-04-02 | 2957.00 | | 2001 ....
113. From the following table, write a SQL query to find those employees whose name ends with 'S' and six characters long. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+----------+------------+------------+---------+------------+-------- 68736 | ADNRES | CLERK | 67858 | 1997-05-23 | 1200.00 | | 2001 69000 | JULIUS | CLERK | 66928 | 1991-12-03 | 1050.00 | | 3001 (2 rows)
114. From the following table, write a SQL query to find those employees who joined in any month, but the month name contain the character ‘A’. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+----------+------------+------------+---------+------------+-------- 66928 | BLAZE | MANAGER | 68319 | 1991-05-01 | 2750.00 | | 3001 65646 | JONAS | MANAGER | 68319 | 1991-04-02 | 2957.00 | | 2001 67858 | SCARLET | ANALYST | 65646 | 1997-04-19 | 3100.00 | | 2001 64989 | ADELYN | SALESMAN | 66928 | 1991-02-20 | 1700.00 | 400.00 | 3001 ....
115. From the following table, write a SQL query to find those employees who joined in any month, but the name of the month contain the character ‘A’ in second position. Return complete information about the employees. Go to the editor
Sample table: employees
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+----------+------------+------------+---------+------------+-------- 66928 | BLAZE | MANAGER | 68319 | 1991-05-01 | 2750.00 | | 3001 68736 | ADNRES | CLERK | 67858 | 1997-05-23 | 1200.00 | | 2001 69324 | MARKER | CLERK | 67832 | 1992-01-23 | 1400.00 | | 1001 (3 rows)
Practice Online
More to Come!
Structure of employee Database:
Do not submit any solution of the above exercises at here, if you want to contribute go to the appropriate exercise page.
SQL: Tips of the Day
Inner join vs Where
CREATE TABLE table1 ( id INT, name VARCHAR(20) ); CREATE TABLE table2 ( id INT, name VARCHAR(20) );
The execution plan for the query using the inner join:
- with inner join
EXPLAIN PLAN FOR SELECT * FROM table1 t1 INNER JOIN table2 t2 ON t1.id = t2.id;
SELECT * FROM TABLE (DBMS_XPLAN.DISPLAY);
-- 0 select statement
-- 1 hash join (access("T1"."ID"="T2"."ID"))
-- 2 table access full table1
-- 3 table access full table2
And the execution plan for the query using a WHERE clause.
-- with where clause
EXPLAIN PLAN FOR SELECT * FROM table1 t1, table2 t2 WHERE t1.id = t2.id;
SELECT * FROM TABLE (DBMS_XPLAN.DISPLAY);
-- 0 select statement
-- 1 hash join (access("T1"."ID"="T2"."ID"))
-- 2 table access full table1
-- 3 table access full table2
Ref : https://bit.ly/3ssEEiE
- Weekly Trends
- Java Basic Programming Exercises
- SQL Subqueries
- Adventureworks Database Exercises
- C# Sharp Basic Exercises
- SQL COUNT() with distinct
- JavaScript String Exercises
- JavaScript HTML Form Validation
- Java Collection Exercises
- SQL COUNT() function
- SQL Inner Join
- JavaScript functions Exercises
- Python Tutorial
- Python Array Exercises
- SQL Cross Join
- C# Sharp Array Exercises